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The following is a bunch of links <a elements. ONLY one of them has a substring "long" as a value for the attribute href
<a class="c1" href= "very_lpng string" > name1 </a> <a class="g2" href= "verylong string" > name2 </a> // The one that I need <a class="g4" href= "very ling string" > name3 </a> <a class="g5g" href= "very ng string" > name4 </a> ................... I need to click the link whose href has substring "long" in it. How can I do this?
PS: driver.findElement(By.partialLinkText("long")).click(); // b/c it chooses by the name
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To click a link, we can use the link text locator which matches the text enclosed within the anchor tag. We can also use the partial link text locator which matches the text enclosed within the anchor tag partially. NoSuchElementException is thrown if there is no matching element found by both these locators.
This will get you the generic link: selenium. FindElement(By. XPath("xpath=//a[contains(@href,'listDetails.do')")).
We can click a href link with Selenium webdriver. There are multiple ways to achieve this. First of all we need to identify the link with the help of the locators like link text and partial link text. The link text locator identifies the element whose text matches with text enclosed within the anchor tag.
I need to click the link who's href has substring "long" in it. How can I do this?
With the beauty of CSS selectors.
your statement would be...
driver.findElement(By.cssSelector("a[href*='long']")).click(); This means, in english,
Find me any 'a' elements, that have the
hrefattribute, and that attributecontains'long'
You can find a useful article about formulating your own selectors for automation effectively, as well as a list of all the other equality operators. contains, starts with, etc... You can find that at: http://ddavison.io/css/2014/02/18/effective-css-selectors.html
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