I am casting my String variables to integer and double. I want to check whether the String variable contains valid Integer or Double value at runtime.
I us following code but it not works for me.
String var1="5.5";
String var2="6";
Object o1=var1;
Object o2=var2;
if (o1 instanceof Integer)
{
qt += Integer.parseInt( var1);// Qty
}
if (o2 instanceof Double)
{
wt += Double.parseDouble(var2);// Wt
}
Try to parse the int and catch the exception if it fails:
String var1="5.5";
try {
qt += Integer.parseInt( var1);
}
catch (NumberFormatException nfe) {
// wasn't an int
}
You can use patterns to detect if a string is an integer or not :
Pattern pattern = Pattern.compile("^[-+]?\\d+(\\.\\d+)?$");
Matcher matcher = pattern.matcher(var1);
if (matcher.find()){
// Your string is a number
} else {
// Your string is not a number
}
You will have to find the correct pattern (I haven't used them for awhile) or someone could edit my answer with the correct pattern.
*EDIT** : Found a pattern for you. edited the code. I did not test it but it is taken from java2s site which also offer an even more elgant approach (copied from the site) :
public static boolean isNumeric(String string) {
return string.matches("^[-+]?\\d+(\\.\\d+)?$");
}
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