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The error can be avoided by using the isset() method. This method will check whether the declared array key has null value or not. If it does it returns false else it returns true for all cases. This type of error occurs with arrays when we use the key of an array, which is not set.
The Offset that does not exist in an array then it is called as an undefined offset. Undefined offset error is similar to ArrayOutOfBoundException in Java. If we access an index that does not exist or an empty offset, it will lead to an undefined offset error.
The array_key_exists() is an inbuilt function of PHP that is used to check whether a specific key or index is present inside an array or not. The function returns true if the specified key is found in the array otherwise returns false.
Is it possible to check the value of a certain key in a PHP array in 1 IF statement? Right now, in order to not throw an index offset error I have to check if the key is set, then check its value.
if (isset($array[$key]))
{
if ($array[$key] == $x)
{
// do stuff
}
}
(sorry, accidentally put ! in first IF originally)
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