How to check multiple elements has same class using jquery?

Question

Is it possible to minify this selector?

if ($("#element1").hasClass("highlight") && $("#element2").hasClass("highlight") && $("#element3").hasClass("highlight") && $("#element4").hasClass("highlight") && $("#element5").hasClass("highlight")) {
  $("#newstyle).css("visibility", "visible");
};

I already tried

if ($("#element1, #element2, #element3, #element4, #element5").hasClass("highlight"))

and

if ($("#element1 && #element2 && #element3 && #element4 && #element5").hasClass("highlight"))

...but that's incorrect.

Basically I have many conditions the same like this: 5 specified elements hasClass XYZ. So I'd appreciate it to compress it.

Answer 1

You're on the right track. I should note that I'm assuming the pattern element1, element2, element3 isn't really how your IDs are, that you just used that in the question...

I'd probably turn it a bit on its head: Use a group of selectors with #element:not(.highlight) and if the result is empty (length == 0), they all either have it or don't exist.

if (!$("#element1:not(.highlight), #element2:not(.highlight), #element3:not(.highlight), #element4:not(.highlight), #element5:not(.highlight)").length) {

  $("#newstyle").css("visibility", "visible");

}

Example where they all have the class:

if (!$("#element1:not(.highlight), #element2:not(.highlight), #element3:not(.highlight), #element4:not(.highlight), #element5:not(.highlight)").length) {

  $("#newstyle").css("visibility", "visible");

}

<div id="element1" class="highlight"></div>
<div id="element2" class="highlight"></div>
<div id="element3" class="highlight"></div>
<div id="element4" class="highlight"></div>
<div id="element5" class="highlight"></div>
<div id="newstyle" style="visibility: hidden">I'm visible!</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

And where at least one of them doesn't:

Example where they all have the class:

if (!$("#element1:not(.highlight), #element2:not(.highlight), #element3:not(.highlight), #element4:not(.highlight), #element5:not(.highlight)").length) {

  $("#newstyle").css("visibility", "visible");

}

<div id="element1" class="highlight"></div>
<div id="element2" class="highlight"></div>
<div id="element3"></div>
<div id="element4" class="highlight"></div>
<div id="element5" class="highlight"></div>
<div id="newstyle" style="visibility: hidden">I'm visible!</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

If it's all the same class, as in your example, we can be a bit more concise:

if (!$("#element1, #element2, #element3, #element4, #element5").not(".highlight").length) {

  $("#newstyle").css("visibility", "visible");

}

Example where they all have the class:

if (!$("#element1, #element2, #element3, #element4, #element5").not(".highlight").length) {

  $("#newstyle").css("visibility", "visible");

}

<div id="element1" class="highlight"></div>
<div id="element2" class="highlight"></div>
<div id="element3" class="highlight"></div>
<div id="element4" class="highlight"></div>
<div id="element5" class="highlight"></div>
<div id="newstyle" style="visibility: hidden">I'm visible!</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

And where at least one doesn't:

if (!$("#element1, #element2, #element3, #element4, #element5").not(".highlight").length) {

  $("#newstyle").css("visibility", "visible");

}

<div id="element1" class="highlight"></div>
<div id="element2" class="highlight"></div>
<div id="element3"></div>
<div id="element4" class="highlight"></div>
<div id="element5" class="highlight"></div>
<div id="newstyle" style="visibility: hidden">I'm visible!</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

Answer 2

You can use attribute begins with selector "[id^=element]" passed to Array.prototype.every(), return $(el).is(".highlight") from .every() callback

// Note `$("#element1, #element2, #element3, #element4, #element5")`
// can be substituted for `$("[id^=element]")` here
if ([].every.call($("[id^=element]"), el => $(el).is(".highlight"))) {
  // do stuff
  console.log("ok");
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="element1" class="highlight"></div>
<div id="element2" class="highlight"></div>
<div id="element3" class="highlight"></div>
<div id="element4" class="highlight"></div>
<div id="element5" class="highlight"></div>

Alternatively you can check if element which has .id beginning with "element" and where .className contains "highlight" followed by whitespace or end of value .length is equal to .length of elements having .id beginning with "element"

if ($("[id^=element][class~=highlight]").length === $("[id^=element]").length) {
  console.log("ok")
}

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="element1" class="highlight"></div>
<div id="element2" class="highlight"></div>
<div id="element3" class="highlight"></div>
<div id="element4" class="highlight"></div>
<div id="element5" class="highlight"></div>