How to check iphone model using swift

Question

How we can check model of iPhone (e.g iPhone 4/ iPhone5) in Swift. Using following code I can check whether it is iPhone of iPod.

let iphoneModel = UIDevice.currentDevice().model
if (iphoneModel == "iPhone"){
        println("Iphone 4")
    }

I need to know specifically which iPhone model it is.

Answer 1

Swift 4 + iPhone Xr, Xs, Xs Max support

import UIKit

enum UIUserInterfaceIdiom : Int {
    case Unspecified
    case phone
    case pad
}

struct ScreenSize {
    static let screenWidth = UIScreen.main.bounds.size.width
    static let screenHeight = UIScreen.main.bounds.size.height
    static let screenMaxLength = max(ScreenSize.screenWidth, ScreenSize.screenHeight)
    static let screenMinLength = min(ScreenSize.screenWidth, ScreenSize.screenHeight)
}

struct DeviceType {
    static let iPhone4OrLess  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength < 568.0
    static let iPhoneSE = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 568.0
    static let iPhone8 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 667.0
    static let iPhone8Plus = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 736.0
    static let iPhoneXr = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPhoneXs = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 812.0
    static let iPhoneXsMax = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPad = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 1024.0
}

And use :

 if DeviceType.iPhoneXsMax {
      print("is Max here")
 }