How to check if Location Services are enabled?

Question

You can use the below code to check whether gps provider and network providers are enabled or not.

LocationManager lm = (LocationManager)context.getSystemService(Context.LOCATION_SERVICE);
boolean gps_enabled = false;
boolean network_enabled = false;

try {
    gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
} catch(Exception ex) {}

try {
    network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
} catch(Exception ex) {}

if(!gps_enabled && !network_enabled) {
    // notify user
    new AlertDialog.Builder(context)
        .setMessage(R.string.gps_network_not_enabled)
        .setPositiveButton(R.string.open_location_settings, new DialogInterface.OnClickListener() {
            @Override
            public void onClick(DialogInterface paramDialogInterface, int paramInt) {
                context.startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
            }
        })
        .setNegativeButton(R.string.Cancel,null)
        .show();    
}

And in the manifest file, you will need to add the following permissions

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

I use this code for checking:

public static boolean isLocationEnabled(Context context) {
    int locationMode = 0;
    String locationProviders;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);

        } catch (SettingNotFoundException e) {
            e.printStackTrace();
            return false;
        }

        return locationMode != Settings.Secure.LOCATION_MODE_OFF;

    }else{
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        return !TextUtils.isEmpty(locationProviders);
    }


} 

As now in 2020

Latest, Best and shortest way is

@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        // This is a new method provided in API 28
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        return lm.isLocationEnabled();
    } else {
        // This was deprecated in API 28
        int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                Settings.Secure.LOCATION_MODE_OFF);
        return (mode != Settings.Secure.LOCATION_MODE_OFF);
    }
}

Migrate to AndroidX and use

implementation 'androidx.appcompat:appcompat:1.3.0'

and use LocationManagerCompat

In Java

private boolean isLocationEnabled(Context context) {
    LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return LocationManagerCompat.isLocationEnabled(locationManager);
}

In Kotlin

private fun isLocationEnabled(context: Context): Boolean {
    val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return LocationManagerCompat.isLocationEnabled(locationManager)
}

You may use this code to direct users to Settings, where they can enable GPS:

    locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
        new AlertDialog.Builder(context)
            .setTitle(R.string.gps_not_found_title)  // GPS not found
            .setMessage(R.string.gps_not_found_message) // Want to enable?
            .setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialogInterface, int i) {
                    owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                }
            })
            .setNegativeButton(R.string.no, null)
            .show();
    }