How to check if elements in list 'a' meet conditions in list 'b'?

Question

I have a list of numbers:

a = [3, 6, 20, 24, 36, 92, 130]

And a list of conditions:

b = ["2", "5", "20", "range(50,100)", ">120"]

I want to check if a number in 'a' meets one of the conditions in 'b' and if yes, put these numbers in list 'c'

In above case:

c = [20, 92, 130]

I created this code what seems to do what I want:

c = []
for x in a:
    for y in b:
        if "range" in y:
            rangelist = list(eval(y))
            if x in rangelist:
                c.append(x)
        elif ">" in y or "<" in y:
            if eval(str(x) + y):
                c.append(x)
        else:
            if x == eval(y):
                c.append(x)

However my list 'a' can be very big.
Is there not an easier and faster way to obtain what I want?

Answer 1

Building on @user2357112's suggestion, you can create a list of functions for all your conditions, then pass each number, to each function to determine whether the number meets any of the conditions, or not.

In [1]: a = [3, 6, 20, 24, 36, 92, 130]

In [2]: conditions = [lambda x:x==2, lambda x:x==5, lambda x:x==20, lambda x: x in range(50, 100), lambda x: x > 120]  # List of lambda functions

In [3]: output = list()

In [4]: for number in a:
   ...:     if any(func(number) for func in conditions): # Check if the number satisfies any of the given conditions by passing the number as an argument to each function
   ...:         output.append(number)         

In [5]: output
Out[5]: [20, 92, 130]