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I want to check if array contains object or not. I am not trying to compare values just want to check in my array if object is present or not?
Ex.
$arr = ['a','b','c'] // normal
$arr = [{ id: 1}, {id: 2}] // array of objects
$arr = [{id: 1}, {id:2}, 'a', 'b'] // mix values
So how can i check if array contains object
639
some() The some() method tests whether at least one element in the array passes the test implemented by the provided function. It returns true if, in the array, it finds an element for which the provided function returns true; otherwise it returns false.
Now that we have a simple Array of numbers, we use Math. min() or Math. max() to return the min/max values from our new Y value array. The spread operator allows us to insert an array into the built in function.
Use the inbuilt ES6 function some() to iterate through each and every element of first array and to test the array. Use the inbuilt function includes() with second array to check if element exist in the first array or not. If element exist then return true else return false.
You can use some method which tests whether at least one element in the array passes the test implemented by the provided function.
let arr = [{id: 1}, {id:2}, 'a', 'b'];
let exists = arr.some(a => typeof a == 'object');
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