Looks ugly:
df_cut = df_new[              (              (df_new['l_ext']==31) |              (df_new['l_ext']==22) |              (df_new['l_ext']==30) |              (df_new['l_ext']==25) |              (df_new['l_ext']==64)              )             ]   Does not work:
df_cut = df_new[(df_new['l_ext'] in [31, 22, 30, 25, 64])]   Is there an elegant and working solution of the above "problem"?
isin() function check whether values are contained in Series. It returns a boolean Series showing whether each element in the Series matches an element in the passed sequence of values exactly.
Use isin
df_new[df_new['l_ext'].isin([31, 22, 30, 25, 64])] 
                        You can use pd.DataFrame.query:
select_values = [31, 22, 30, 25, 64] df_cut = df_new.query('l_ext in @select_values')   In the background, this uses the top-level pd.eval function.
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