Looks ugly:
df_cut = df_new[ ( (df_new['l_ext']==31) | (df_new['l_ext']==22) | (df_new['l_ext']==30) | (df_new['l_ext']==25) | (df_new['l_ext']==64) ) ]
Does not work:
df_cut = df_new[(df_new['l_ext'] in [31, 22, 30, 25, 64])]
Is there an elegant and working solution of the above "problem"?
isin() function check whether values are contained in Series. It returns a boolean Series showing whether each element in the Series matches an element in the passed sequence of values exactly.
Use isin
df_new[df_new['l_ext'].isin([31, 22, 30, 25, 64])]
You can use pd.DataFrame.query
:
select_values = [31, 22, 30, 25, 64] df_cut = df_new.query('l_ext in @select_values')
In the background, this uses the top-level pd.eval
function.
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