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Other than using a set of or statements
isinstance( x, np.float64 ) or isinstance( x, np.float32 ) or isinstance( np.float16 )
Is there a cleaner way to check of a variable is a floating type?
886
float32 is a 32 bit number - float64 uses 64 bits. That means that float64's take up twice as much memory - and doing operations on them may be a lot slower in some machine architectures. However, float64's can represent numbers much more accurately than 32 bit floats. They also allow much larger numbers to be stored.
np. float64 is a class, not a function ( type(np.
NVIDIA GPUs can run operations in float16 faster than in float32, and TPUs can run operations in bfloat16 faster than float32.
You can use np.floating:
In [11]: isinstance(np.float16(1), np.floating)
Out[11]: True
In [12]: isinstance(np.float32(1), np.floating)
Out[12]: True
In [13]: isinstance(np.float64(1), np.floating)
Out[13]: True
Note: non-numpy types return False:
In [14]: isinstance(1, np.floating)
Out[14]: False
In [15]: isinstance(1.0, np.floating)
Out[15]: False
to include more types, e.g. python floats, you can use a tuple in isinstance:
In [16]: isinstance(1.0, (np.floating, float))
Out[16]: True
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