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Is there an easy way to verify that the given character has a special regex function?
Of course I can collect regex characters in a list like ['.', "[", "]", etc.] to check that, but I guess there is a more elegant way.
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Then using the search() method we will search if any special character is present in the string or not. If no character is found the search() method will return None and then we can print that the string is accepted.
There is a method for matching specific characters using regular expressions, by defining them inside square brackets. For example, the pattern [abc] will only match a single a, b, or c letter and nothing else.
Python has two major implementations, the built in re and the regex library. Ruby 1.8, Ruby 1.9, and Ruby 2.0 and later versions use different engines; Ruby 1.9 integrates Oniguruma, Ruby 2.0 and later integrate Onigmo, a fork from Oniguruma. The primary regex crate does not allow look-around expressions.
You could use re.escape. For example:
>>> re.escape("a") == "a"
True
>>> re.escape("[") == "["
False
The idea is that if a character is a special one, then re.escape returns the character with a backslash in front of it. Otherwise, it returns the character itself.
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