I have an instance of UIBezierPath
and I want to change the color of the stroke to something other than black. Does anyone know how to do this in Swift?
With Swift 5, UIColor
has a setStroke()
method. setStroke()
has the following declaration:
func setStroke()
Sets the color of subsequent stroke operations to the color that the receiver represents.
Therefore, you can use setStroke()
like this:
strokeColor.setStroke() // where strokeColor is a `UIColor` instance
The Playground code below shows how to use setStroke()
alongside UIBezierPath
in order to draw a circle with a green fill color and a light grey stroke color inside a UIView
subclass:
import UIKit
import PlaygroundSupport
class MyView: UIView {
override func draw(_ rect: CGRect) {
// UIBezierPath
let newRect = CGRect(
x: bounds.minX + ((bounds.width - 79) * 0.5 + 0.5).rounded(.down),
y: bounds.minY + ((bounds.height - 79) * 0.5 + 0.5).rounded(.down),
width: 79,
height: 79
)
let ovalPath = UIBezierPath(ovalIn: newRect)
// Fill
UIColor.green.setFill()
ovalPath.fill()
// Stroke
UIColor.lightGray.setStroke()
ovalPath.lineWidth = 5
ovalPath.stroke()
}
}
let myView = MyView(frame: CGRect(x: 0, y: 0, width: 200, height: 300))
PlaygroundPage.current.liveView = myView
Let's assume you want to use the color red instead to stroke a rounded rectangle; This is how you do it in Swift 3 :
// Drawing the border of the rounded rectangle:
let redColor = UIColor.red
redColor.setStroke() // Stroke subsequent views with a red color
let roundedRectagle = CGRect(x: 0,y: 0, width: 90,height: 20)
let rectangleBorderPath = UIBezierPath(roundedRect: roundedRectangle,cornerRadius: 5)
roundedRectangle.borderWidth = 1
roundedRectangle.stroke() // Apply the red color stroke on this view
The second and last lines of the above code are important in answering your question.I hope this answer is helpful.
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