How to change color of drawable shapes in android

Question

I am developing small android application in which I set drawable resource as background for linear layout. Now what I want to do change background color of linear layout dynamically, but within drawable resource. My code looks like :

//  bcd.xml <selector xmlns:android="http://schemas.android.com/apk/res/android">  <item>             <shape>         <gradient             android:endColor="#22000000"             android:startColor="#22000000"             android:angle="270" />         <stroke             android:width="3dp"             android:color="@color/white" />         <corners             android:radius="3dp" />         <padding             android:left="10dp"             android:top="10dp"             android:right="10dp"             android:bottom="10dp" />     </shape> </item> 

<LinearLayout  android:id="@+id/lin_llt" android:layout_width="wrap_content" android:layout_height="wrap_content" > 

and I set background for linear layout in my activity like this...

parentLayout = (LinearLayout) view.findViewById(R.id.lin_llt); parentLayout.setBackgroundResource(R.drawable.bcd); 

Now what I want to do i want to change color of my drawable resource that mean change color of my linear layout with rounded corner and padding define in drawable..

I tried this in following way

ShapeDrawable bgShape = (ShapeDrawable )parentLayout.getBackground(); bgShape.getPaint().setColor(Color.BLACK); 

but its not working for me. any other solution .

So how to do it... Need help... thank you...

Answer 1

Change the layout color dynamically

LinearLayout Layout = (LinearLayout) findViewById(R.layout.id); Layout.setBackgroundColor(Color.parseColor("#ffffff")); 

Dynamically set the background color gradient

View layout = findViewById(R.id.mainlayout);  GradientDrawable gd = new GradientDrawable(         GradientDrawable.Orientation.TOP_BOTTOM,         new int[] {0xFF616261,0xFF131313}); gd.setCornerRadius(0f);  layout.setBackgroundDrawable(gd); 

Answer 2

You could try something like this :

Drawable sampleDrawable = context.getResources().getDrawable(R.drawable.balloons);  sampleDrawable.setColorFilter(new PorterDuffColorFilter(0xffff00,PorterDuff.Mode.MULTIPLY)); 

and for more you could refer to :

How to change colors of a Drawable in Android?

Change drawable color programmatically

Android: Change Shape Color in runtime

http://pastebin.com/Hd2aU4XC

You could also try this :

private static final int[] FROM_COLOR = new int[]{49, 179, 110}; private static final int THRESHOLD = 3;  public void onCreate(Bundle savedInstanceState) {     super.onCreate(savedInstanceState);     setContentView(R.layout.test_colors);      ImageView iv = (ImageView) findViewById(R.id.img);     Drawable d = getResources().getDrawable(RES);     iv.setImageDrawable(adjust(d)); }  private Drawable adjust(Drawable d) {     int to = Color.RED;      //Need to copy to ensure that the bitmap is mutable.     Bitmap src = ((BitmapDrawable) d).getBitmap();     Bitmap bitmap = src.copy(Bitmap.Config.ARGB_8888, true);     for(int x = 0;x < bitmap.getWidth();x++)         for(int y = 0;y < bitmap.getHeight();y++)             if(match(bitmap.getPixel(x, y)))                  bitmap.setPixel(x, y, to);      return new BitmapDrawable(bitmap); }  private boolean match(int pixel) {     //There may be a better way to match, but I wanted to do a comparison ignoring     //transparency, so I couldn't just do a direct integer compare.     return Math.abs(Color.red(pixel) - FROM_COLOR[0]) < THRESHOLD && Math.abs(Color.green(pixel) - FROM_COLOR[1]) < THRESHOLD && Math.abs(Color.blue(pixel) - FROM_COLOR[2]) < THRESHOLD; } 

as given in How to change colors of a Drawable in Android?