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Is there any way to catch the exception from UrlFetchApp.fetch?
I thought I can use response.getResponseCode() to check the response code, but I'm not able to, for e.g when there is 404 error, the script not continue and just stop at UrlFetchApp.fetch
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fetch() will always be sync, no matter whether you declare your function as async or not, due to the GAS-API-design.
URL Fetch. This service allows scripts to access other resources on the web by fetching URLs. A script can use the UrlFetch service to issue HTTP and HTTPS requests and receive responses. The UrlFetch service uses Google's network infrastructure for efficiency and scaling purposes.
UrlFetchApp. Fetch resources and communicate with other hosts over the Internet. This service allows scripts to communicate with other applications or access other resources on the web by fetching URLs. A script can use the URL Fetch service to issue HTTP and HTTPS requests and receive responses.
Edit: This parameter is now documented here.
You can use the undocumented advanced option "muteHttpExceptions" to disable exceptions when a non-200 status code is returned, and then inspect the status code of the response. More information and an example is available on this issue.
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