How to cast from double to int round off the top

Question

I have got code:

double dd=2.99;
int ii=(int)(dd);//ii==2

I would like to have 3 in ii. Is there any fast and simple method?

Answer 1

You want Math.round() or - if you always want to round up - Math.ceil(). Similarly, there is a Math.floor() to always round down.

Being really picky, you should note that Math.round( double ) returns a long, so there is a possible loss of precision if you want to store the result in an int (for really large doubles).

Answer 2

Use Math.ceil(dd). It'll round any number up to the nearest integer. Likewise, Math.floor(dd) would round it down while Math.round(dd) would round down/up depending on which is closer.

For the record, the Math class contains loads of useful mathematical methods.