How to call super in PHP?

Question

I have a classB which extends classA.

In both classA and classB I define the method fooBar().

In fooBar() of classB I want to call fooBar() of classA at the beginning.

Just the way I'm used to, from Objective-C. Is that possible in PHP? And if so, how?

Answer 1

parent::fooBar(); 

Straight from the manual:

The ... double colon, is a token that allows access to ... overridden properties or methods of a class.

...

Example #3 Calling a parent's method

<?php class MyClass {     protected function myFunc() {         echo "MyClass::myFunc()\n";     } }  class OtherClass extends MyClass {     // Override parent's definition     public function myFunc()     {         // But still call the parent function         parent::myFunc();         echo "OtherClass::myFunc()\n";     } }  $class = new OtherClass(); $class->myFunc(); ?> 

Answer 2

Just a quick note because this doesn't come up as easy on Google searches, and this is well documented in php docs if you can find it. If you have a subclass that needs to call the superclass's constructor, you can call it with:

parent::__construct(); // since PHP5 

An example would be if the super class has some arguments in it's constructor and it's implementing classes needs to call that:

class Foo {    public function __construct($lol, $cat) {     // Do stuff specific for Foo   }  }  class Bar extends Foo {    public function __construct()(     parent::__construct("lol", "cat");     // Do stuff specific for Bar   }  } 

You can find a more motivating example here.