Menu
I have such code:
function allValid() { $('input').each(function(index) { if(something) { return false; } }); return true; } which always returns true as return false; affects anonymous inner function. Is there an easy way to call outer function's return?
PS. I am not looking for a workaround, just want to know the answer to original question. If the answer is "not possible" it is fine.
862
Nested function is private to containing function Only the containing function can access the nested function. We cannot access it anywhere outside the function. This is because the inner function is defined in the scope of the outer function (or containing function).
A closure is a feature in JavaScript where an inner function has access to the outer (enclosing) function's variables — a scope chain. The closure has three scope chains: it has access to its own scope — variables defined between its curly brackets. it has access to the outer function's variables.
The return statement is used to return a particular value from the function to the function caller. The function will stop executing when the return statement is called. The return statement should be the last statement in a function because the code after the return statement will be unreachable.
Yeah, store it in a local variable.
function allValid() { var allGood = true; $('input').each(function (index) { if (something) { allGood = false; } }); return allGood; } If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
