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i have take google signin in my website :
<script src="https://apis.google.com/js/platform.js" async defer></script>
<script>
function onSignIn(googleUser) {
var profile = googleUser.getBasicProfile();
//console.log('ID: ' + profile.getId()); // Do not send to your backend! Use an ID token instead.
//console.log('Image URL: ' + profile.getImageUrl());
//console.log('Name: ' + profile.getName());
//console.log('Email: ' + profile.getEmail());
var user_uname = profile.getName();
var user_email = profile.getEmail();
alert(user_uname);
}
</script>
and here is a button to login google:
<div class="g-signin2" data-onsuccess="onSignIn"></div>
i want to give user google signin but the problem is whenever page is load onSignIn() function is called automatically. i want it only on button click. can anybody help me?
351
Best solution is to render sign-in button only when user is not signed in.
<html>
<head>
<meta name="google-signin-client_id" content="YOUR_CLIENT_ID">
</head>
<body>
<script>
function onSignIn(googleUser) {
var profile = googleUser.getBasicProfile();
var user_name = profile.getName();
alert(user_name);
}
function onLoad() {
gapi.load('auth2,signin2', function() {
var auth2 = gapi.auth2.init();
auth2.then(function() {
// Current values
var isSignedIn = auth2.isSignedIn.get();
var currentUser = auth2.currentUser.get();
if (!isSignedIn) {
// Rendering g-signin2 button.
gapi.signin2.render('google-signin-button', {
'onsuccess': 'onSignIn'
});
}
});
});
}
</script>
<div id="google-signin-button"></div>
<script src="https://apis.google.com/js/platform.js?onload=onLoad" async defer></script>
</body>
</html>
I done it by declaring global js variable as false
var isFirstGoogle = 0;
Then to check this variable
if(isFirstGoogle)
{
//wont enter here first time
}
isFirstGoogle = 1;
So next time when I click on button the above method will be called as now isFirstGoogle = 1;
Hope this help!! It's a temporary thing I know but it's working for me.
31
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