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(function($) {
$.fn.top_islides = function(){
var ajax_init = function(){
init_islides();
setTimeout(function(){picmove()},300);
};
//.....
};
})(jQuery);
call it in doucument ready in another file
$('#top_slides').top_islides();
$('#top_slides').top_islides().ajax_init();
I thought it should work ,I got an error, what's the problem?
518
function someFunction() { //do stuff } $(document). ready(function(){ //Load City by State $('#billing_state_id'). live('change', someFunction); $('#click_me'). live('click', function() { //do something someFunction(); }); });
You need to use the script tag. As almost everything we do when using jQuery reads or manipulates the document object model (DOM), we need to make sure that we start adding events etc. as soon as the DOM is ready. If you want an event to work on your page, you should call it inside the $(document).
A jQuery plugin is simply a new method that we use to extend jQuery's prototype object. By extending the prototype object you enable all jQuery objects to inherit any methods that you add. As established, whenever you call jQuery() you're creating a new jQuery object, with all of jQuery's methods inherited.
Do it like this:
(function($) {
//Assuming $.fn.top_islides is defined
$.fn.top_islides.ajax_init = function(){
init_islides();
setTimeout(picmove,300);
};
//.....
})(jQuery);
Or
(function($) {
$.fn.top_islides = function(){
var ajax_init = function(){
init_islides();
setTimeout(picmove,300);
};
return {
ajax_init: ajax_init
};
});
//.....
})(jQuery);
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