In below code, your_method is called when your_command is executed in slack
from flask_slack import Slack
slack = Slack(app)
app.add_url_rule('/', view_func=slack.dispatch)
@slack.command('your_command', token='your_token',
team_id='your_team_id', methods=['POST'])
def your_method(**kwargs):
text = kwargs.get('text')
return text
How to call this your_method from another function in this python program.
Eg.
def print:
a = your_method('hello','world')
This gives me error =>
Traceback (most recent call last):
File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1381, in handle_user_exception
reraise(exc_type, exc_value, tb)
File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1475, in full_dispatch_request
rv = self.dispatch_request()
return func(**kwargs)
File "sample.py", line 197
a = your_method('hello','world')
TypeError: your_method() takes exactly 0 arguments (1 given)
Based on the signature, tis function only accepts keyword arguments.
def your_method(**kwargs):
You call it with positional arguments.
your_method('hello', 'world')
You either need to change the signature
def your_method(*args, **kwargs)
or call it differently
your_method(something='hello', something_else='world')
You cannot do this. Methods decorated with the route decorator cannot accept arguments passed in by you. View function arguments are reserved for route parameters, like the following:
@app.route('/user/<username>')
def show_user_profile(username):
# show the user profile for that user
return 'User %s' % username
@app.route('/post/<int:post_id>')
def show_post(post_id):
# show the post with the given id, the id is an integer
return 'Post %d' % post_id
Moreover, Flask does not want you to call on these methods directly, they are intended to be executed only in response to a request input from Flask.
A better practice would be to abstract whatever logic you are trying to do into another function.
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