I am trying to calculate the error rate of the training data I'm using.
I believe I'm calculating the error incorrectly. The formula is as shown:
y
is calculated as shown:
I am calculating this in the function fitPoly(M)
at line 49
. I believe I am incorrectly calculating y(x(n))
, but I don't know what else to do.
Below is the Minimal, Complete, and Verifiable example.
import numpy as np
import matplotlib.pyplot as plt
dataTrain = [[2.362761180904257019e-01, -4.108125266714775847e+00],
[4.324296163702689988e-01, -9.869308732049049127e+00],
[6.023323504115264404e-01, -6.684279243433971729e+00],
[3.305079685397107614e-01, -7.897042003779912278e+00],
[9.952423271981121200e-01, 3.710086310489402628e+00],
[8.308127402955634011e-02, 1.828266768673480147e+00],
[1.855495407116576345e-01, 1.039713135916495501e+00],
[7.088332047815845138e-01, -9.783208407540947560e-01],
[9.475723071629885697e-01, 1.137746192425550085e+01],
[2.343475721257285427e-01, 3.098019704040922750e+00],
[9.338350584099475160e-02, 2.316408265530458976e+00],
[2.107903139601833287e-01, -1.550451474833406396e+00],
[9.509966727520677843e-01, 9.295029459100994984e+00],
[7.164931165416982273e-01, 1.041025972594300075e+00],
[2.965557300301902011e-03, -1.060607693351102121e+01]]
def strip(L, xt):
ret = []
for i in L:
ret.append(i[xt])
return ret
x1 = strip(dataTrain, 0)
y1 = strip(dataTrain, 1)
# HELP HERE
def getY(m, w, D):
y = w[0]
y += np.sum(w[1:] * D[:m])
return y
# HELP ABOVE
def dataMatrix(X, M):
Z = []
for x in range(len(X)):
row = []
for m in range(M + 1):
row.append(X[x][0] ** m)
Z.append(row)
return Z
def fitPoly(M):
t = []
for i in dataTrain:
t.append(i[1])
w, _, _, _ = np.linalg.lstsq(dataMatrix(dataTrain, M), t)
w = w[::-1]
errTrain = np.sum(np.subtract(t, getY(M, w, x1)) ** 2)/len(x1)
print('errTrain: %s' % (errTrain))
return([w, errTrain])
#fitPoly(8)
def plotPoly(w):
plt.ylim(-15, 15)
x, y = zip(*dataTrain)
plt.plot(x, y, 'bo')
xw = np.arange(0, 1, .001)
yw = np.polyval(w, xw)
plt.plot(xw, yw, 'r')
#plotPoly(fitPoly(3)[0])
def bestPoly():
m = 0
plt.figure(1)
plt.xlim(0, 16)
plt.ylim(0, 250)
plt.xlabel('M')
plt.ylabel('Error')
plt.suptitle('Question 3: training and Test error')
while m < 16:
plt.figure(0)
plt.subplot(4, 4, m + 1)
plotPoly(fitPoly(m)[0])
plt.figure(1)
plt.plot(fitPoly(m)[1])
#plt.plot(fitPoly(m)[2])
m+= 1
plt.figure(3)
plt.xlabel('t')
plt.ylabel('x')
plt.suptitle('Question 3: best-fitting polynomial (degree = 8)')
plotPoly(fitPoly(8)[0])
print('Best M: %d\nBest w: %s\nTraining error: %s' % (8, fitPoly(8)[0], fitPoly(8)[1], ))
bestPoly()
Updated: This solution uses numpy's np.interp
which will connect the points as a kind of "best fit". We then use your error function to find the difference between this interpolated line and the predicted y values for the degree of each polynomial.
import numpy as np
import matplotlib.pyplot as plt
import itertools
dataTrain = [
[2.362761180904257019e-01, -4.108125266714775847e+00],
[4.324296163702689988e-01, -9.869308732049049127e+00],
[6.023323504115264404e-01, -6.684279243433971729e+00],
[3.305079685397107614e-01, -7.897042003779912278e+00],
[9.952423271981121200e-01, 3.710086310489402628e+00],
[8.308127402955634011e-02, 1.828266768673480147e+00],
[1.855495407116576345e-01, 1.039713135916495501e+00],
[7.088332047815845138e-01, -9.783208407540947560e-01],
[9.475723071629885697e-01, 1.137746192425550085e+01],
[2.343475721257285427e-01, 3.098019704040922750e+00],
[9.338350584099475160e-02, 2.316408265530458976e+00],
[2.107903139601833287e-01, -1.550451474833406396e+00],
[9.509966727520677843e-01, 9.295029459100994984e+00],
[7.164931165416982273e-01, 1.041025972594300075e+00],
[2.965557300301902011e-03, -1.060607693351102121e+01]
]
data = np.array(dataTrain)
data = data[data[:, 0].argsort()]
X,y = data[:, 0], data[:, 1]
fig,ax = plt.subplots(4, 4)
indices = list(itertools.product([0,1,2,3], repeat=2))
for i,loc in enumerate(indices, start=1):
xx = np.linspace(X.min(), X.max(), 1000)
yy = np.interp(xx, X, y)
w = np.polyfit(X, y, i)
y_pred = np.polyval(w, xx)
ax[loc].scatter(X, y)
ax[loc].plot(xx, y_pred)
ax[loc].plot(xx, yy, 'r--')
error = np.square(yy - y_pred).sum() / X.shape[0]
print(error)
plt.show()
This prints out:
2092.19807848
1043.9400277
1166.94550318
252.238810889
225.798905379
155.785478366
125.662973726
143.787869281
6553.66570273
10805.6609259
15577.8686283
13536.1755299
108074.871771
213513916823.0
472673224393.0
1.01198058355e+12
Visually, it plots out this:
From here, it's just a matter of saving those errors to a list and finding the minimum.
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