How to bypass Laravel Exception handling

Question

I have a method that checks if a user has valid Session info. This is supposed to throw an Exception, Guzzle\Http\Exception\BadResponseException but when I try to catch it :

catch (Guzzle\Http\Exception\BadResponseException $e) 
{
    return false;
} 
return true

Laravel doesn't get to this code and immediately starts it's own error handling. And ideas on how to bypass Laravels own implementation and use my own Catch.

EDIT: I just found out Laravel uses the same Exception handler as Symfony, so I also added the Symfony2 tag.

EDIT 2:

I sort of fixed the issue by disabling Guzzle exceptions and checking the return header manually. It's a bit of a short cut but in this case, it does the job. Thanks for the responses!

Answer 1

Actually this exception can be catched in Laravel, you just have to respect (and understand) namespacing:

If you have

namespace App;

and you do

catch (Guzzle\Http\Exception\BadResponseException $e) 

PHP understands that you are trying to

catch (\App\Guzzle\Http\Exception\BadResponseException $e) 

So, for it to work you just need a root slash:

catch (\Guzzle\Http\Exception\BadResponseException $e) 

And it will work.