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How to build grammar of default value with boost spirit?

I am analyzing some scientific text whose format is something like

Keyword
{ 1.0  22.2  59.6 'cm' 'yes' }

I am new to spirit, and after studying the document, I can use spirit to solve the fixed-format keyword .

But to the following format, I don't know how to build grammar. My question is: In the scientific keyword I've meet, certain items of data can be defaulted to a built-in default value. The keyword description indicates when defaults can be applied. There are two ways of setting quantities to their default values. Firstly, by ending a data record prematurely with a slash '}' the quantities remaining unspecified are set to their default values. Secondly, selected quantities positioned before '}' can be defaulted by entering n* where n is the number of consecutive quantities to be defaulted. For example, 3* causes the next three quantities in the keyword data to be given their default values.

For example,

Person
{ 'Tom' 188 80 'male' 32 }

say 'male' and '32' are default value, and its equivalent can be:

Person
{ 'Tom' 188 88 2* }

or

Person
{ 'Tom' 188 88 'male' 1* }

or

Person
{ 'Tom' 188 88 }

I've searched past posts, and this gives me some idea, but how can I write the rule of n*?

like image 821
spanent Avatar asked Apr 29 '11 20:04

spanent


2 Answers

The parser you're asking for is very complex as it has to solve several tasks:

  • handle missing elements in the end
  • handle the "2*" syntax as a replacement for missing elements at the end
  • properly not only parse all valid inputs but also fill a given data structure with the matched values

The trick here is to utilize qi::attr in different ways:

  • to supply default values for missing elements:

    qi::int_ | qi::attr(180)
    

    i.e. either match an integer or use default value 180

  • to supply all remaining values for the "2*" syntax (as @vines suggested):

    "2*" >> qi::attr(attr2)
    

    i.e. if 2* was matched use default value attr2 (which is a fusion::vector).

Overall, I came up with this solution, which seems to parse and return the default values just fine (even if it looks very complex):

#include <string>
#include <iostream>

#include <boost/spirit/include/qi.hpp>
#include <boost/fusion/include/vector.hpp>

int main()
{
    namespace qi = boost::spirit::qi;
    namespace fusion = boost::fusion;

    // the attribute passed to the parser has to match (in structure) the 
    // parser, requiring to create nested fusion::vector's
    typedef fusion::vector<std::string, int>              attribute1_type;
    typedef fusion::vector<int, attribute1_type>          attribute2_type;
    typedef fusion::vector<int, attribute2_type>          attribute3_type;

    // overall attribute type
    typedef fusion::vector<std::string, attribute3_type>  attribute_type;

    // initialize attributes with default values
    attribute1_type attr1("male", 32);
    attribute2_type attr2(80, attr1);
    attribute3_type attr3(180, attr2);

    qi::rule<std::string::iterator, std::string()> quoted_string =
        "'" >> *~qi::char_("'") >> "'";

    qi::rule<std::string::iterator, attribute_type(), qi::space_type> data =
        qi::lit("Person") >> "{" 
            >>  quoted_string 
            >> -(   ("4*" >> qi::attr(attr3))
                |   (qi::int_ | qi::attr(180))
                    >> -(   ("3*" >> qi::attr(attr2))
                        |   (qi::int_ | qi::attr(80))
                            >> -(   ("2*" >> qi::attr(attr1))
                                |   (quoted_string | qi::attr("male"))
                                    >> -(   "1*"  
                                        |   qi::int_ 
                                        |   qi::attr(32)
                                        )
                                )
                        )
                )
        >> "}";

    std::string in1 = "Person\n{ 'Tom' 188 80 'male' 32 }";
    attribute_type fullattr1;
    if (qi::phrase_parse(in1.begin(), in1.end(), data, qi::space, fullattr1))
        std::cout << fullattr1 << std::endl;

    std::string in2 = "Person\n{ 'Tom' 188 80 'male' }";
    attribute_type fullattr2;
    if (qi::phrase_parse(in2.begin(), in2.end(), data, qi::space, fullattr2))
        std::cout << fullattr2 << std::endl;

    std::string in3 = "Person\n{ 'Tom' 188 3* }";
    attribute_type fullattr3;
    if (qi::phrase_parse(in3.begin(), in3.end(), data, qi::space, fullattr3))
        std::cout << fullattr3 << std::endl;

    return 0;
}

Splitting the rule into separate rules (as @vines suggests) would require the input to be parsed more than once, which is why I used this nested structure of sequences and alternatives.

like image 95
hkaiser Avatar answered Nov 20 '22 19:11

hkaiser


I've just came up with the generalized solution, though it's a bit more complex =)
It handles both "premature brace" and multiple arbitrary skip specifiers. Here's it:

#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/phoenix_core.hpp>
#include <boost/spirit/include/phoenix_operator.hpp>
#include <boost/fusion/include/adapt_struct.hpp>
#include <boost/fusion/include/io.hpp>

#include <iostream>
#include <string>


namespace qi = boost::spirit::qi;
namespace ph = boost::phoenix;

struct numbers { int i1, i2, i3, i4; };

BOOST_FUSION_ADAPT_STRUCT
(numbers,
    (int, i1)
    (int, i2)
    (int, i3)
    (int, i4)
)

template <typename Iterator, typename Skipper>
struct Grammar : public qi::grammar <Iterator, numbers(), Skipper>
{
    Grammar() : Grammar::base_type(start, "numbers")
    {
    using qi::int_;

    // This rule resets the skip counter:
    init_skip = qi::eps[ph::ref(skp) = 0];

    // This rule parses the skip directive ("n*") and sets the skip counter:
    skip_spec = qi::omit[ (qi::lexeme[ int_ >> "*" ])[ph::ref(skp) = qi::_1] ];

    // This rule checks if we should skip the field, and if so, decrements
    // the skip counter and returns the value given to it (the default one).
    // If not, it tries to parse the int.
    // If int fails to parse, the rule resorts the default value again,
    // thus handling the "premature brace" case.
    int_dflt %= qi::eps(ph::ref(skp) > 0)[--ph::ref(skp)] >> qi::attr(qi::_r1) | int_ | qi::attr(qi::_r1);

    // And this is the grammar:
    start %= init_skip >>
             "{" >> -skip_spec >> int_dflt(-1)
                 >> -skip_spec >> int_dflt(-1)
                 >> -skip_spec >> int_dflt(-1)
                 >> -skip_spec >> int_dflt(-1)
                 >> "}";
    }

    // the skip counter itself:
    int skp;

    qi::rule <Iterator, numbers(), Skipper> start;
    qi::rule <Iterator, Skipper> skip_spec, init_skip;
    qi::rule <Iterator, int(int), Skipper> int_dflt;
};




int main (int argc, char **argv)
{
    using std::cout;
    using std::endl;

    std::string s = argv[1];

    numbers result;

    std::string::iterator ib = s.begin();
    std::string::iterator ie = s.end();
    bool r = qi::phrase_parse(ib, ie, Grammar<std::string::iterator, qi::space_type>(), qi::space, result );

    if (r && ib == ie)
    {
        cout << boost::fusion::tuple_open('[');
        cout << boost::fusion::tuple_close(']');
        cout << boost::fusion::tuple_delimiter(", ");

        cout << "Parsing succeeded\n";
        cout << "got: " << boost::fusion::as_vector(result) << endl;
    }
    else
    {
        cout << "Parsing failed\n";
        cout << "err: " << std::string(ib, ie) << endl;
    }

    return 0;
}

PS: Note that the Skipper template argument has nothing to do with field skipping — it's simply the type of the whitespace-skipping parser used by the grammar.

like image 4
vines Avatar answered Nov 20 '22 18:11

vines