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How to binary (de)serialize object into/form string?

I need serialize objects into String and deserialize.

I readed sugestion on stackoverflow and make this code:

class Data implements Serializable {
int x = 5;
int y = 3;   
}

public class Test {
public static void main(String[] args) {

    Data data = new Data();

    String out;

    try {
        // zapis
        ByteArrayOutputStream baos = new ByteArrayOutputStream();
        ObjectOutputStream oos = new ObjectOutputStream(baos);

        oos.writeObject(data);

        out = new String(baos.toByteArray());
        System.out.println(out);

        // odczyt.==========================================

        ByteArrayInputStream bais = new ByteArrayInputStream(out.getBytes());

        ObjectInputStream ois = new ObjectInputStream(bais);

        Data d = (Data) ois.readObject();

        System.out.println("d.x = " + d.x);
        System.out.println("d.y = " + d.y);

    } catch (FileNotFoundException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    } catch (ClassNotFoundException e) {
        e.printStackTrace();
    }

}

}

but I get error:

java.io.StreamCorruptedException: invalid stream header: EFBFBDEF
at java.io.ObjectInputStream.readStreamHeader(ObjectInputStream.java:801)
at java.io.ObjectInputStream.<init>(ObjectInputStream.java:298)
at p.Test.main(Test.java:37)

Why? I expected: d.x = 5 d.y = 3

how to do in good way? Ah. I don't want to write this object in file. I have to have it in string format.

like image 797
LunaVulpo Avatar asked Nov 26 '12 15:11

LunaVulpo


2 Answers

It is not entirely true to say that conversion to string corrupts the data. Conversion to "UTF-8" does because it is not bijective (some characters are 2 bytes but not all 2 bytes sequences are allowed as character sequences), while "ISO-8859-1" is bijective (1 character of a String is a byte and vice-versa).

Base64 encoding is not very space-efficient compared to this.

This is why I would recommend:

/**
 * Serialize any object
 * @param obj
 * @return
 */
public static String serialize(Object obj) {
    try {
        ByteArrayOutputStream bo = new ByteArrayOutputStream();
        ObjectOutputStream so = new ObjectOutputStream(bo);
        so.writeObject(obj);
        so.flush();
        // This encoding induces a bijection between byte[] and String (unlike UTF-8)
        return bo.toString("ISO-8859-1");
    } catch (Exception e) {
        e.printStackTrace();
    }
}
/**
 * Deserialize any object
 * @param str
 * @param cls
 * @return
 */
public static <T> T deserialize(String str, Class<T> cls) {
    // deserialize the object
    try {
        // This encoding induces a bijection between byte[] and String (unlike UTF-8)
        byte b[] = str.getBytes("ISO-8859-1"); 
        ByteArrayInputStream bi = new ByteArrayInputStream(b);
        ObjectInputStream si = new ObjectInputStream(bi);
        return cls.cast(si.readObject());
    } catch (Exception e) {
        e.printStackTrace();
    }
}
like image 56
ngrislain Avatar answered Sep 21 '22 18:09

ngrislain


Use
ByteArrayInputStream bais = new ByteArrayInputStream(baos.toByteArray()); instead of ByteArrayInputStream bais = new ByteArrayInputStream(out.getBytes());, since the String conversion corrupts the data (because of the encoding).

If you really need to store the result in a String, you need a safe way to store arbitrary bytes in a String. One way of doing that is to us Base64-encoding.

A totally different approach would have been to not use the standard Java serialization for this class, but create your own Data to/from String converter.

like image 40
Aleksander Blomskøld Avatar answered Sep 17 '22 18:09

Aleksander Blomskøld