How to avoid Undefined offset error?

Question

This is a part of my script:

$one = 0;
$two = 0;
$three = 0;

$data = 'a-b-c';

$data = explode("-", $data);
$one = $data[0];
$two = $data[1];
$three = $data[2];

No problems so far but $data sometimes can be

$data = 'a-b-c';

and sometimes

$data = 'a-b';

In case of $data = 'a-b'; I get Undefined offset: 3 error. Is it some way how to avoid this error?

Answer 1

Wrap the assignment into an if-block:

if(isset($data[0])) {
    $one = $data[0];
}

...

This now checks if this array item isset, if not you just do not assign it and no error will show up.

Answer 2

Assumes that at least one will always exist

$data = 'a-b';

list($one, $two, $three) = explode("-", $data . '-0-0');