How to avoid short-circuit evaluation on

Question

Try this:

([model1, model2].map(&:valid?)).all?

It'll return true if both are valid, and create the errors on both instances.

& works just fine.

irb(main):007:0> def a
irb(main):008:1> puts "a"
irb(main):009:1> false
irb(main):010:1> end
=> nil

irb(main):011:0> def b
irb(main):012:1> puts "b"
irb(main):013:1> true
irb(main):014:1> end
=> nil

irb(main):015:0> a && b
a
=> false

irb(main):016:0> a & b
a
b
=> false

irb(main):017:0> a and b
a
=> false

How about:

if [model1.valid?,model2.valid?].all?
  ...
end

Works for me.

Evaluate them separately and store the result in a variable. Then use a simple && between those booleans :)