How to avoid repeating std::forward for the same variable

Question

Suppose that I have this template function:

template <typename T>
void foo(T &&t) {
    std::forward<T>(t).foo();
    std::forward<T>(t).bar();
    std::forward<T>(t).baz();

}

Notice that I had to repeat std::forward multiple times for the same variable (to make sure that if T has ref-qualified foo()/bar()/baz(), the correct one will be called).

Is there a way to avoid repeating std::forward? It is not just redundant, but error-prone as well because I may forget to add std::forward somewhere.

Answer 1

Notice that I had to repeat std::forward multiple times for the same variable (to make sure that if T has ref-qualified foo()/bar()/baz(), the correct one will be called).

You should not repeat std::forward - you should only use it with the last call:

template <typename T>
void foo(T &&t) {
    t.foo();
    t.bar();
    std::forward<T>(t).baz();

}

The way you wrote it, if the actual argument is rvalue, ref-qualified foo() may steal contents of t, and subsequent calls will not work as intended.