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How to append new value to xts object without creating a new one

Tags:

r

xts

I have an xts object, for example

ts=xts(seq(10),seq(Sys.Date(),Sys.Date()+10,length.out=10))

and need to add a new point, for example

(Sys.Date()+11, 11)

I have tried

ts[Sys.Date()+11] <- 11

but it doesnt work. I would prefer to avoid creating a new xts object. Is there an elegant way to do this.

like image 288
LouisChiffre Avatar asked Dec 01 '11 10:12

LouisChiffre


1 Answers

You can use c or rbind on an xts object to append row-wise:

c(ts, xts(11, Sys.Date()+11))

EDIT :

Note that this produces a warning mismatched types: converting objects to numeric. To remove the warning, first coerce the value to numeric, e.g:

c(ts, xts(as.integer(11), Sys.Date()+11))

           [,1]
2011-12-01    1
2011-12-02    2
2011-12-03    3
2011-12-04    4
2011-12-05    5
2011-12-06    6
2011-12-07    7
2011-12-08    8
2011-12-09    9
2011-12-11   10
2011-12-12   11
like image 186
Andrie Avatar answered Sep 22 '22 17:09

Andrie