Python newbie here. I've searched quite a bit for a solution to this but nothing quite fits what I need. I would like to allocate an empty array at the start of my program that has a rows and b columns. I came up with a solution but encountered an interesting problem that I didn't expect. Here's what I had:
a = 7
b = 5
array_ab = [['?'] * b] * a
which produces
[['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?']]
However, if I try to change a single element, it treats every row as the same object and effectively changes the entire column to that element. So for example
array_ab[4][2] = '1'
produces
[['?', '?', '1', '?', '?'],
['?', '?', '1', '?', '?'],
['?', '?', '1', '?', '?'],
['?', '?', '1', '?', '?'],
['?', '?', '1', '?', '?'],
['?', '?', '1', '?', '?'],
['?', '?', '1', '?', '?']]
Clearly I need a better way to create the blank array than by multiplication. Is there a solution to this in python? (It was so simple in FORTRAN!)
We can create a copy of an array by using the assignment operator (=). In Python, Assignment statements do not copy objects, they create bindings between a target and an object. When we use = operator user thinks that this creates a new object; well, it doesn't.
For example, the following code creates an array of zeros with the same shape as the x input array: x = np. array([[1,2],[3,4],[5,6]], dtype=np.
Changing size of numpy Array in Python Size of a numpy array can be changed by using resize() function of the NumPy library. refcheck- It is a boolean that checks the reference count.
The elements of an array occupy a contiguous block of memory, and once created, its size cannot be changed. A dynamic array can, once the array is filled, allocate a bigger chunk of memory, copy the contents from the original array to this new space, and continue to fill the available slots.
Something along the lines of
In [12]: a = 5
In [13]: b = 7
In [14]: array_ab = [ [ '?' for i in xrange(a) ] for j in xrange(b) ]
In [15]: array_ab
Out[15]:
[['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?']]
In [16]: array_ab[4][2] = '1'
In [17]: array_ab
Out[17]:
[['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '1', '?', '?'],
['?', '?', '?', '?', '?'],
['?', '?', '?', '?', '?']]
In particular, you're using list comprehensions and xrange.
If you are going to use your array for numerical computations, and can live with importing an external library, then I would suggest looking at numpy
.
It provides an array class and lots of useful array operations.
Creating an MxN array is simply
import numpy as np
A = np.empty((M,N)) # Empty array
B = np.zeros((M,N)) # Array filled with zeros
Indexing is then done like
x = A[i,j]
A[4,2] = 1
row1 = A[0, :] # or simply A[0]
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