How to allocate an array inside fortran routine "called" from C

Question

I think title says what I need. I know we can use "asd" function to do this, but for some reasons I need to do the allocation in Fortran (i.e. in subroutine "asd_"). Here is the C code:

#include <stdio.h>

void asd(float **c) {
  *c = (float *) malloc (2*sizeof(float));
  **c =123;
  *(*c+1)=1234;
}

void asd_(float **c);

main () {
  float *c;
  asd_(&c);
// asd(&c); would do the job perfectly
  printf("%f %f \n",c[0],c[1]);
  return 0;
}

And here is the Fortran code:

  subroutine asd(c)

  implicit none

  real, pointer, allocatable ::c(:)

  print *, associated(c)
  if(.not. associated(c))  allocate(c(2))

  end subroutine 

This randomly gives segmentation fault. Any help would be appreciated.

Answer 1

The Fortran 2003 ISO C Binding provides a portable way to do this. It is implemented in many compilers. Here is example code.

#include <stdio.h>

void test_mem_alloc ( float ** array );

int main ( void ) {

   float * array;
   test_mem_alloc (&array);

   printf ( "Values are: %f %f\n", array [0], array [1] );

   return 0;
}

and

subroutine test_mem_alloc ( c_array_ptr ) bind (C, name="test_mem_alloc")

   use, intrinsic :: iso_c_binding
   implicit none

   type (c_ptr), intent (out) :: c_array_ptr
   real (c_float), allocatable, dimension (:), target, save :: FortArray

   allocate (FortArray (1:2) )
   FortArray = [ 2.5_c_float, 4.4_c_float ]

   c_array_ptr = c_loc (FortArray)

end subroutine test_mem_alloc