I'm sending email through below code:
msg = MIMEText(u'<a href="www.google.com">abc</a>')
msg['Subject'] = 'subject'
msg['From'] = 'xxx'
msg['To'] = 'xxx'
s = smtplib.SMTP(xxx, 25)
s.sendmail(xxx, xxx, msg.as_string())
what I want to receive is
abc
what I actually received is:
<a href="www.google.com">abc</a>
Python offers a ` library to send emails- “SMTP lib”. “smtplib” creates a Simple Mail Transfer Protocol client session object which is used to send emails to any valid email id on the internet. The Port number used here is '587'.
link() method in Python is used to create a hard link. This method creates a hard link pointing to the source named destination.
This worked for me :)
email_body = """<pre>
Congratulations! We've successfully created account.
Go to the page: <a href="https://www.google.com/">click here</a>
Thanks,
XYZ Team.
</pre>"""
msg = MIMEText(email_body ,'html')
O/P: Congratulations! We've successfully created account.
Go to the page: click here
Thanks,
XYZ Team.
You should specify 'html'
as the subtype -
msg = MIMEText(u'<a href="www.google.com">abc</a>','html')
Without specifying the subtype separately , the subtype defaults to 'plain'
(plain-text). From documentations -
class email.mime.text.MIMEText(_text[, _subtype[, _charset]])
A subclass of MIMENonMultipart, the MIMEText class is used to create MIME objects of major type text. _text is the string for the payload. _subtype is the minor type and defaults to plain.
(Emphasis mine) .
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