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How to add extra object to tasty pie return json in python django

In Django project i get two objects when i receive the JSON response

data.meta and data.objects

This is my Resource

class MyResource(ModelResource):
    def dehydrate(self, bundle):
        bundle.data["absolute_url"] = bundle.obj.get_absolute_url()
        bundle.data['myfields'] = MyDataFields
        return bundle
    class Meta:

        queryset = MyData.objects.all()
        resource_name = 'weather'
        serializer = Serializer(formats=['json'])
        ordering = MyDataFields

now i want to other field in json like

data.myfields

but if i do the above way then that field is added to every object like

data.objects.myfields

how can i do data.myfields

like image 389
Mirage Avatar asked Nov 09 '12 04:11

Mirage


2 Answers

a better approach IMHO would be to use alter_list_data_to_serialize, the function made to override/add fields to the data before making the response:

    def alter_list_data_to_serialize(self, request, data):
        data['meta']['current_time'] = datetime.strftime(datetime.utcnow(), "%Y/%m/%d") 
        return data

This way you don't override all the mimetype/status code for all calls and it's cleaner.

like image 122
Hassek Avatar answered Oct 21 '22 16:10

Hassek


One way to do this is by overriding Tastypie ModelResource's get_list method.

import json
from django.http import HttpResponse

...

class MyResource(ModelResource):

    ...

    def get_list(self, request, **kwargs):
        resp = super(MyResource, self).get_list(request, **kwargs)

        data = json.loads(resp.content)

        data['myfields'] = MyDataFields

        data = json.dumps(data)

        return HttpResponse(data, content_type='application/json', status=200)
like image 25
Blake Avatar answered Oct 21 '22 15:10

Blake