how to add custom color to flutter?

Question

I want to change the color of AppBar and use a custom color for it, I tried many options but none seem to work. Is there anything I'm missing?

import 'package:flutter/material.dart';

final ThemeData CompanyThemeData = new ThemeData(
  brightness: Brightness.light,
  primaryColorBrightness: Brightness.light,
  accentColor: CompanyColors.black[500],
  accentColorBrightness: Brightness.light
);
  
class CompanyColors {
  CompanyColors._(); // this basically makes it so you can instantiate this class
 
 static const _blackPrimaryValue = 0xFF000000;

  static const MaterialColor black = const MaterialColor(
    _blackPrimaryValue,
    const <int, Color>{
      50:  const Color(0xFFe0e0e0),
      100: const Color(0xFFb3b3b3),
      200: const Color(0xFF808080),
      300: const Color(0xFF4d4d4d),
      400: const Color(0xFF262626),
      500: const Color(_blackPrimaryValue),
      600: const Color(0xFF000000),
      700: const Color(0xFF000000),
      800: const Color(0xFF000000),
      900: const Color(0xFF000000),
    },
  );
}

and then I have used it in main.dart as

Widget build(BuildContext context) {
    return new MaterialApp(
      title: 'Flutter Demo',
      theme: new ThemeData(
        // This is the theme of your application.
        //
        // Try running your application with "flutter run". You'll see the
        // application has a blue toolbar. Then, without quitting the app, try
        // changing the primarySwatch below to Colors.green and then invoke
        // "hot reload" (press "r" in the console where you ran "flutter run",
        // or press Run > Flutter Hot Reload in IntelliJ). Notice that the
        // counter didn't reset back to zero; the application is not restarted.
        primarySwatch:Theme1.CompanyColors.black[50],
      ),
      home: new MyHomePage(title: 'Flutter Demo Home Page'),
    );
  }

but after execution it says

type Color is not of subtype MaterialColor

Answer 1

basically flutter uses color AARRGGBB format you can use below color code with any color property like:

new Container(color: const Color(0xff2980b9));

AA = transparency

RR = red

GG = green

BB = blue

now if you want to create custom color 8-digit code from 6-digit color code then just append transparency (AA) value to it

Transparency percentages Following are some example transparency percentages and their hex values

100% - FF
95% - F2
90% - E6
85% - D9
80% - CC
75% - BF
70% - B3
65% - A6
60% - 99
55% - 8C
50% - 80
45% - 73
40% - 66
35% - 59
30% - 4D
25% - 40
20% - 33
15% - 26
10% - 1A
5% - 0D
0% - 00

in my case i always use AA = ff because 6-digit color has ff transparency. for 6-digit color best site

Answer 2

There are several ways to do it, but this is the method I prefer to use. It's dead simple.

Create a custom

MaterialColor myColor = MaterialColor(0xFF880E4F, color);

Create a map and as you will see below that I modify the opacity channel from 50 through to 900 to give you the various color degrees of opacity.

Map<int, Color> color =
{
50:Color.fromRGBO(4,131,184, .1),
100:Color.fromRGBO(4,131,184, .2),
200:Color.fromRGBO(4,131,184, .3),
300:Color.fromRGBO(4,131,184, .4),
400:Color.fromRGBO(4,131,184, .5),
500:Color.fromRGBO(4,131,184, .6),
600:Color.fromRGBO(4,131,184, .7),
700:Color.fromRGBO(4,131,184, .8),
800:Color.fromRGBO(4,131,184, .9),
900:Color.fromRGBO(4,131,184, 1),
};

Same works for Color.fromRGBA if you prefer using Alpha over Opacity.

I would like to point out that I saw you were trying to do this.

primarySwatch: Colors.black[500]

This will give you the an error. You have to use the base MaterialColor you created. Using the color degree modifiers will make the compiler unhappy.

Answer 3

It's a MaterialColor object (not Color) you should assign for a swatch property, providing color values for the ten different luminances.

Many people suggested adjusting the alpha/opacity value of the colors used in the MaterialColor. It's actually a big mistake because it will result in making your element translucent without providing color variety of different shades.

Please consider using this solution for a better approach.

Flutter: Creating a custom color swatch for MaterialColor

MaterialColor createMaterialColor(Color color) {
  List strengths = <double>[.05];
  final swatch = <int, Color>{};
  final int r = color.red, g = color.green, b = color.blue;

  for (int i = 1; i < 10; i++) {
    strengths.add(0.1 * i);
  }
  strengths.forEach((strength) {
    final double ds = 0.5 - strength;
    swatch[(strength * 1000).round()] = Color.fromRGBO(
      r + ((ds < 0 ? r : (255 - r)) * ds).round(),
      g + ((ds < 0 ? g : (255 - g)) * ds).round(),
      b + ((ds < 0 ? b : (255 - b)) * ds).round(),
      1,
    );
  });
  return MaterialColor(color.value, swatch);
}

Answer 4

You can create a Seprate class.

static const PrimaryColor =  Color(0xFF808080);
static const PrimaryAssentColor =  Color(0xFF808080);
static const PrimaryDarkColor =  Color(0xFF808080);
static const ErroColor =  Color(0xFF808080);