I want to select a file on the local hard disk when I click a "Browse" button.
I don't have any idea how to use the OpenFileDialog
control. Can anyone help me?
3 Answers. Show activity on this post. private void button1_Click(object sender, EventArgs e) { int size = -1; OpenFileDialog openFileDialog1 = new OpenFileDialog(); DialogResult result = openFileDialog1. ShowDialog(); // Show the dialog.
Press f5 key from keyword or from start button in Visual Studio. Now browse the file and click on upload button to upload the file in database. Now move to Sql Server and check file is uploaded. Also check the path folder where actual file is saving.
Forms. OpenFileDialog component opens the Windows dialog box for browsing and selecting files. To open and read the selected files, you can use the OpenFileDialog. OpenFile method, or create an instance of the System.
These links explain it with examples
http://dotnetperls.com/openfiledialog
http://www.geekpedia.com/tutorial67_Using-OpenFileDialog-to-open-files.html
private void button1_Click(object sender, EventArgs e) { int size = -1; OpenFileDialog openFileDialog1 = new OpenFileDialog(); DialogResult result = openFileDialog1.ShowDialog(); // Show the dialog. if (result == DialogResult.OK) // Test result. { string file = openFileDialog1.FileName; try { string text = File.ReadAllText(file); size = text.Length; } catch (IOException) { } } Console.WriteLine(size); // <-- Shows file size in debugging mode. Console.WriteLine(result); // <-- For debugging use. }
var FD = new System.Windows.Forms.OpenFileDialog(); if (FD.ShowDialog() == System.Windows.Forms.DialogResult.OK) { string fileToOpen = FD.FileName; System.IO.FileInfo File = new System.IO.FileInfo(FD.FileName); //OR System.IO.StreamReader reader = new System.IO.StreamReader(fileToOpen); //etc }
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