JavaPairRDD<String, Float> counts = ones
.reduceByKey(new Function2<Float, Float, Float>() {
@Override
public Float call(Float i1, Float i2) {
return i1 + i2;
}
});
My output looks like this:
id,value
100002,23.47
100003,42.78
200003,50.45
190001,30.23
I would like the output to be sorted by value like:
200003,50.45
100003,42.78
190001,30.23
100002,23.47
How do I achieve this?
Scala has a nice sortBy
method. Could not find the Java equivalent, but this is the scala implementation:
def sortBy[K](
f: (T) => K,
ascending: Boolean = true,
numPartitions: Int = this.partitions.size)
(implicit ord: Ordering[K], ctag: ClassTag[K]): RDD[T] =
this.keyBy[K](f)
.sortByKey(ascending, numPartitions)
.values
So, basically similar to the above, but it add a key instead of swapping forward and backwards. I use it like this: .sortBy(_._2)
(sort by picking the second element of the tuple).
I think there is no specific API to sort the data on value.
May be you need to do below steps:
1) Swap key and value
2) Use sortByKey API
3) Swap key and value
Look at the more details about sortByKey in beloe reference:
https://spark.apache.org/docs/1.0.0/api/java/org/apache/spark/api/java/JavaPairRDD.html#sortByKey%28boolean%29
for swap, we can use Scala Tuple API:
http://www.scala-lang.org/api/current/index.html#scala.Tuple2
For example, I have Java Pair RDD from the below function.
JavaPairRDD<String, Integer> counts = ones.reduceByKey(new Function2<Integer, Integer, Integer>() {
@Override
public Integer call(Integer i1, Integer i2) {
return i1 + i2;
}
});
Now, To swap key and value, you can use below code:
JavaPairRDD<Integer, String> swappedPair = counts.mapToPair(new PairFunction<Tuple2<String, Integer>, Integer, String>() {
@Override
public Tuple2<Integer, String> call(Tuple2<String, Integer> item) throws Exception {
return item.swap();
}
});
Hope this helps. You need to take care of the data types.
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