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How may I sort a list alphabetically using jQuery?

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How do I sort a list alphabetically in jQuery?

Put the list in an array, use JavaScript's . sort() , which is by default alphabetical, then convert the array back to a list.

How do I sort a list alphabetically?

Select the list you want to sort. Go to Home > Sort. Set Sort by to Paragraphs and Text. Choose Ascending (A to Z) or Descending (Z to A).

How do you sort names in alphabetical order in JavaScript?

JavaScript Array sort() The sort() sorts the elements of an array. The sort() overwrites the original array. The sort() sorts the elements as strings in alphabetical and ascending order.


Something like this:

var mylist = $('#myUL');
var listitems = mylist.children('li').get();
listitems.sort(function(a, b) {
   return $(a).text().toUpperCase().localeCompare($(b).text().toUpperCase());
})
$.each(listitems, function(idx, itm) { mylist.append(itm); });

From this page: http://www.onemoretake.com/2009/02/25/sorting-elements-with-jquery/

Above code will sort your unordered list with id 'myUL'.

OR you can use a plugin like TinySort. https://github.com/Sjeiti/TinySort


You do not need jQuery to do this...

function sortUnorderedList(ul, sortDescending) {
  if(typeof ul == "string")
    ul = document.getElementById(ul);

  // Idiot-proof, remove if you want
  if(!ul) {
    alert("The UL object is null!");
    return;
  }

  // Get the list items and setup an array for sorting
  var lis = ul.getElementsByTagName("LI");
  var vals = [];

  // Populate the array
  for(var i = 0, l = lis.length; i < l; i++)
    vals.push(lis[i].innerHTML);

  // Sort it
  vals.sort();

  // Sometimes you gotta DESC
  if(sortDescending)
    vals.reverse();

  // Change the list on the page
  for(var i = 0, l = lis.length; i < l; i++)
    lis[i].innerHTML = vals[i];
}

Easy to use...

sortUnorderedList("ID_OF_LIST");

Live Demo →


$(".list li").sort(asc_sort).appendTo('.list');
//$("#debug").text("Output:");
// accending sort
function asc_sort(a, b){
    return ($(b).text()) < ($(a).text()) ? 1 : -1;    
}

// decending sort
function dec_sort(a, b){
    return ($(b).text()) > ($(a).text()) ? 1 : -1;    
}

live demo : http://jsbin.com/eculis/876/edit


To make this work work with all browsers including Chrome you need to make the callback function of sort() return -1,0 or 1.

see http://inderpreetsingh.com/2010/12/01/chromes-javascript-sort-array-function-is-different-yet-proper/

function sortUL(selector) {
    $(selector).children("li").sort(function(a, b) {
        var upA = $(a).text().toUpperCase();
        var upB = $(b).text().toUpperCase();
        return (upA < upB) ? -1 : (upA > upB) ? 1 : 0;
    }).appendTo(selector);
}
sortUL("ul.mylist");

If you are using jQuery you can do this:

$(function() {

  var $list = $("#list");

  $list.children().detach().sort(function(a, b) {
    return $(a).text().localeCompare($(b).text());
  }).appendTo($list);

});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>

<ul id="list">
  <li>delta</li>
  <li>cat</li>
  <li>alpha</li>
  <li>cat</li>
  <li>beta</li>
  <li>gamma</li>
  <li>gamma</li>
  <li>alpha</li>
  <li>cat</li>
  <li>delta</li>
  <li>bat</li>
  <li>cat</li>
</ul>

Note that returning 1 and -1 (or 0 and 1) from the compare function is absolutely wrong.