string s = "";
for(int i=0;i<10;i++) {
s = s + i;
}
I have been these options to answer this question.
I have this simple code, I just want to know how many string objects will be created by this code.
I have a doubt, Is string s = "";
creates no object. I dont think so, Please make me clear.
If I append string with + operator, it creates new string, so I think It will be a new object created in every iteration of for loop.
So I think there will be 11 objects created. Let me know If I'm incorrect.
String result = "1" + "2" + "3" + "4"; //Compiler will optimise this code to the below line.
String result = "1234"; //So in this case only 1 object will be created??
I followed the below link, but still its not clear.
Link1
Please cover string str
and string str = null
case too. What happens If we dont initialize string and when If I assign string to null. So It will be an object or no object in these two cases.
string str;
string str = null;
Later in the code, If I do.
str = "abc";
Is there any programming way to calculate number of objects?, because I think It may by a debatable topic. How can I be 100 % by doing some programming or by some tool? I cannot see this in IL code.
I have tried the below code,just to make sure whether new object is created or not. It writes 'different' for each iteration. It means it always gives me a different object, So there can a possibility of 10 or 20 objects. because it does not give me info of intermediate state(boxing for i
when doing s = s + i
)
string s = "0";
object obj = s;
for (int i = 0; i < 10; i++)
{
s = s + i;
if (Object.ReferenceEquals(s, obj))
{
Console.Write("Same");
}
else
{
Console.Write("Different");
}
}
I'm not agreed by the statement that string str = ""
does not create any object. I tried this practically.
string s = null;
object obj = null;
if (Object.ReferenceEquals(s, obj))
{
Console.Write("Same");
}
else
{
Console.Write("Different");
}
Code writes "Same", but If I write string s = "";
, It writes "Different" on console.
I have one more doubt now.
what is difference between s = s + i
and s = s + i.ToString()
.
s = s + i.ToString()
IL Code
IL_000f: call instance string [mscorlib]System.Int32::ToString()
IL_0014: call string [mscorlib]System.String::Concat(string, string)
s = s + i
IL Code
IL_000e: box [mscorlib]System.Int32
IL_0013: call string [mscorlib]System.String::Concat(object, object)
So Whats difference between box and instance here
The answer is: 2 String objects are created. str and str2 both refer to the same object.
Two objects will be created for this: String s = new String("abc"); One in the heap and the other in the "string constant pool" (SCP). The reference s will pointing to s always, and GC is not allowed in the SCP area, so all objects on SCP will be destroyed automatically at the time of JVM shutdown.
There are two ways to create a String object: By string literal : Java String literal is created by using double quotes. For Example: String s=“Welcome”; By new keyword : Java String is created by using a keyword “new”.
You will create two String instances.
Well, let's count:
string s = ""; // no new objects created, s assigned to string.Empty from the cache
// 10 times:
for(int i = 0; i < 10; i++) {
// i <- first object to create (boxing): (object) i
// s + i <- second object to create: string.Concat(s, (object) i);
s = s + i;
}
To test that string s = ""
doesn't create an additional object you can put
string s = "";
if (object.ReferenceEquals(s, string.Empty))
Console.Write("Empty string has been cached");
finally, we have 20
objects: 0 + 10 * 2
(10
boxed int
s and 10
string
s). In case of
string result = "1" + "2" + "3" + "4";
as you can see the result
can be and (will be) computed at the compile time, so just one object ("1234"
) will be created. In case of
string str; // just a declaration, str contains trash
string str = null; // no objects created
...
str = "abc"; // an object ("abc") created
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