how make float to integer in awk

Question

I have a variable in my awk code . after some arithmatic operation on this variable and printing (print $1,$2,variable) the result is made like below:

my result

Bama     2   5     Bama     2   5.001 Bama     2   5.002 Bama     2   5.003 Bama     2   5.004 Bama     2   6   Bama     2   6.003 Bama     2   6.004 Bama     2   4.005   

But i want only integer section of my variable print

desired result

Bama     2   5     Bama     2   5 Bama     2   5 Bama     2   5 Bama     2   5 Bama     2   6   Bama     2   6 Bama     2   6 Bama     2   4 

How can I do this?

Answer 1

Truncate it using the int function:

print $1, $2, int( variable ); 

Answer 2

To keep exactly same spacing and everything:

awk -F ' ' '{print $1"     "$2"   "int($3)}' data.lst 

this trims, does not round, so 4.9 will become 4.

A dirty way is to use the point as field separator:

awk -F '.' '{print $1}' data.lst 

Input:

Bama     2   5 Bama     2   5.001 Bama     2   5.002 Bama     2   5.003 Bama     2   5.004 Bama     2   6 Bama     2   6.003 Bama     2   6.004 Bama     2   4.905 

Output in either case:

Bama     2   5 Bama     2   5 Bama     2   5 Bama     2   5 Bama     2   5 Bama     2   6 Bama     2   6 Bama     2   6 Bama     2   4