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How JavaScript promises work behind the scenes

I'm so much confused about what happens behind the scenes when promise is produced and consume. Please clarify my points and sorry for my weak English.

  1. blank object is created with new keyword Promise constructor is called and new keyword set the this of Promise constructor points to the blank object this = blankobject.
  2. Promise constructor receives callback (executor function) in argument and calls the executor function.
  3. executor function receives two callbacks (resolve,reject) as arguments
  4. setTimeout gets called in the executor function and setTimeOut is async code
  5. async code goes to background and then Promise constructor returns Promise object formerly blank object and Promise object reference saved to myPromise.
  6. a variable is created

What happens next ? When then method is called the code of then method goes to background? I imagine it goes to background and a variable is console.log // 10

After main code execution finishes, async code start setTimeout callback begins to execute and after execution finishes promise is fulfilled and resolved function returns value. How is this value stored in promise object and what happens in then method ?

let myPromise = new Promise (
    (resolve, reject) => {

        setTimeout(() => {
            console.log(getIDs)
            resolve(10);

        }, 1500);

    }
)


let a = 10
        myPromise.then(val => {
            console.log(val);

        })
        console.log(a)
like image 607
javascript lover Avatar asked Apr 26 '20 14:04

javascript lover


1 Answers

The following is a simplified implementation of the built-in Promise class. catch and finally have not been implemented.

The function supplied to the Promise constructor is called the executor function, and is invoked immediately and synchronously.

Every promise has a method .then, enabling the chaining of promises.

Functions supplied to .then are always invoked asynchronously on a microtask (note use of queueMicrotask below).

Every time .then is called, a new promise is created and returned.

.then can be called more than once on the same promise, creating a multicast of the result of the promise, and a branching of the promise chain.

A promise can be in one of three states: pending, fulfilled, or rejected. State transitions are unidirectional: you cannot move from fulfilled or rejected, back to pending.

If a promise is resolved with another promise, then the two promise chains are joined and the outer promise takes on the status of the inner promise (which could be pending), until the inner promise resolves.

function Promise(executor) {
  if (!executor) throw "Promise executor undefined"
  let status = "pending", value, thenQ = []

  const then = onFulfilled => {
    let resolver
    // This ensures control does not move to later promises 
    // until prior promises have been resolved.
    const nextPromise = new Promise(resolve => (resolver = resolve))
    // More than one "then" can be registered with each promise.
    thenQ.push((...args) => resolver(onFulfilled(...args)))
    return nextPromise
  }

  // We check if the result is a "thenable"; if so, we treat
  // it as an inner promise, otherwise we simply fulfil with 
  // the result.
  const resolve = result => result?.then ? result.then(fulfil) : fulfil(result)

  // When a promise has been fulfilled, its "thens" can be run.
  const fulfil = result => (status = "fulfilled", value = result, executeThens(value))

  // "Thens" are run asynchronously, on a microtask.
  const executeThens = value => queueMicrotask(() => thenQ.forEach(el => el(value)))

  // The executor is run synchronously.
  executor(resolve)

  return {
    then,
    get status() { return status },
    get value() { return value }
  }
}

// Chaining
new Promise(resolve => {
  console.log('Waiting for step 1...')
  setTimeout(() => resolve("One, two..."), 1500)
})
.then(result => new Promise(resolve => {
  console.log('Waiting for step 2...')
  setTimeout(() => resolve(`${result}three, four`), 1500)
}))
.then(result => console.log(`Chaining result: ${result}.`))

// Branching
const p = new Promise(resolve => {
  console.log('Waiting for step a...')
  setTimeout(() => resolve("Alpha, Bravo..."), 1500)
})

p.then(result => new Promise(resolve => {
  console.log('Waiting for step b1...')
  setTimeout(() => resolve(`${result}Charlie, Delta`), 1500)
})).then(console.log)

p.then(result => {
  console.log('Waiting for step b2...')
  return `${result}Echo, Foxtrot`
}).then(console.log)

See also.

like image 101
Ben Aston Avatar answered Oct 28 '22 05:10

Ben Aston