In swift the following syntax is allowed for flow control
if let constantName = someOptional {
statements
}
In this context what are the semantics of the truth value context ?
Is expression chaining (like below) permitted ?
if let constantName = someOptional && constantName2 = someOptional2 {
statements
}
If so, does the boolean expression short circuit ?
However there is another data type in Swift called Optional, whose default value is a null value ( nil ). You can use optional when you want a variable or constant contain no value in it. An optional type may contain a value or absent a value (a null value). Non technically, you can think optional as a shoe box.
An optional String cannot be used in place of an actual String . To use the wrapped value inside an optional, you have to unwrap it. The simplest way to unwrap an optional is to add a ! after the optional name. This is called "force unwrapping".
Optional binding stores the value that you're binding in a variable. 2. Optional chaining doesn't allows an entire block of logic to happen the same way every time. 2. Optional binding allows an entire block of logic to happen the same way every time.
Swift's optionals are implemented as simple enums, with just a little compiler magic sprinkled around as syntactic sugar.
First someOptional
is checked to see if it's nil or has data. If it's nil, the if-statement just doesn't get executed. If there's data, the data gets unwrapped and assigned to constantName
for the scope of the if-statement. Then the code inside the braces is executed.
if let constantName = someOptional {
statements
}
There's no way to chain this functionality in one if-statement. let constantName = someOptional
does not directly evaluate to a boolean. It's best to think of "if let" as a special keyword.
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