When I splat an array with *
when passing it to a method, then reconstruct an array from it with *
within the method, the identity of the array is not preserved:
a = []
a.object_id # => 69846339548760
def bar *a; a.object_id end
bar(*a) # => 69846339537540
However, when I turn a proc into a block with &
when passing it to a method, then reconstruct a proc from the block with &
within the method, the identity of the proc seems to be preserved:
pr = ->{}
pr.object_id # => 69846339666160
def foo ≺ pr.object_id end
foo(&pr) # => 69846339666160
How is the proc object preserved? Isn't it lost when it is converted to a block? Is this a guaranteed behaviour?
Ruby VM is a stackmachine. When calling a function, it puts all its arguments (including self
) onto the stack and then calls.
How array splat works - it takes array contents and puts it onto the stack, then calls function:
> puts RubyVM::InstructionSequence.compile("a = []; func *a").disasm
== disasm: <RubyVM::InstructionSequence:<compiled>@<compiled>>==========
local table (size: 2, argc: 0 [opts: 0, rest: -1, post: 0, block: -1, kw: -1@-1, kwrest: -1])
[ 2] a
0000 trace 1 ( 1)
0002 newarray 0
0004 setlocal_OP__WC__0 2
0006 putself
0007 getlocal_OP__WC__0 2
0009 splatarray false
0011 opt_send_without_block <callinfo!mid:func, argc:1, ARGS_SPLAT|FCALL>
0013 leave
When passing proc as a block, similar thing happens, but ruby does not have to unwrap proc, it is already a proc.
Added: as per RubySpec's https://github.com/ruby/spec/blob/master/core/proc/block_pass_spec.rb
def revivify; Proc.new; end
it "remains the same object if re-vivified by the target method" do
p = Proc.new {}
p2 = revivify(&p)
p.object_id.should == p2.object_id
p.should == p2
end
this is somewhat standardized behavior, so at least should be followed by Rubinius and jRuby
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