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How does ftell affect a binary file being read in mode 'r' instead of 'rb'?

Tags:

c

file

binary

cs50

I've a rather curious question, not very practical at all really. The error (reading a binary file in r mode) is in plain sight but I'm confused by something else.

Here's the code-

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#include<stdint.h>

#define BUFFER_LEN 512

typedef uint8_t BYTE;

int main()
{
    FILE* memcard = fopen("card.raw", "r");
    BYTE buffer[BUFFER_LEN];
    int count = 0;
    while (fread(buffer, sizeof(*buffer), BUFFER_LEN, memcard) != 0)
    {
        printf("count: %d\n", count++);
    }
    fclose(memcard);
    return 0;
}

Now, card.raw is a binary file, so this reading will go wrong due to being read in r mode instead of rb. But what I'm curious about is that, that loop executes exactly 3 times, in the final execution, it doesn't even read 512 bytes.

Now if I change that loop to

while (fread(buffer, sizeof(*buffer), BUFFER_LEN, memcard) != 0)
{
    printf("ftell: %ld\n", ftell(memcard));
}

It no longer stops at 3 executions. In fact, it keeps going until (presumabely) the end of file. The fread count is still messed up. Many of the reads do not return 512 as elements read. But that is most probably due to the file being opened in r mode and all the encoding errors it's being accompanied with .

ftell shouldn't affect the file itself, then why does including ftell in the loop make it execute more times?

I decided to change the loop a bit more to extract more info-

while ((count = fread(buffer, sizeof(*buffer), BUFFER_LEN, memcard)) != 0)
{
    printf("fread bytes read: %d\n", count);
    printf("ftell: %ld\n", ftell(memcard));
}

This loops just as many times as it would, provided ftell is included in the loop and the first few results look like-

ftell results

Now if I just remove that ftell line completely, it gives me-

without ftell results

Only 3 executions, yet nothing changed.

What's the explanation behind this behaviour?

Note: I know the counts returned by both fread and ftell are probably wrong due to the read mode, that's not my concern though. I'm only curious - why the difference, between including ftell and not including it.

Also, in case it helps, The card.raw file is actually just the cs50 pset4 "memory card". You can get it by wget https://cdn.cs50.net/2019/fall/psets/4/recover/recover.zip and storing the output file in a .zip

Edit: I should mention this was on windows and using clang tools for VS2019. The command line options (checked from VS2019 project properties) looked like-

/permissive- /GS /W3 "Debug\" "Debug\" /Zi /Od "Debug\vc142.pdb" /fp:precise /D "_CRT_SECURE_NO_WARNINGS" /D "_DEBUG" /D "_CONSOLE" /D "_UNICODE" /D "UNICODE" /WX- /Gd /MDd /Fa"Debug\" /EHsc /nologo /Fo"Debug\" /Fp"Debug\Test.pch" /diagnostics:column 

Edit: Also, I did check for ferror inside the loop, with and without ftell, got no errors from it at all. In fact, feof returns 1 after the loop, in both cases.

Edit: I also tried adding a memcard == NULL check right after the fopen, same behaviour.

Edit: To address the answer by @orlp. I did, infact, check for errors. I should definitely have posted it though.

while ((count = fread(buffer, sizeof(*buffer), BUFFER_LEN, memcard)) != 0)
{
    if ((err = ferror(memcard)))
    {           
        fprintf(stderr, "Error code: %d", err);
        perror("Error: ");
        return 1;
    }
    printf("fread bytes read: %d\n", count);
    printf("ftell: %ld\n", ftell(memcard));
}
if ((err = ferror(memcard)))
{
    fprintf(stderr, "Error code: %d", err);
    perror("Error: ");
    return 1;

}

Neither of the 2 if statements are ever triggered.

Edit: I thought we got the answer already, it was ftell resetting the EOF. But I changed the loop to-

while ((count = fread(buffer, sizeof(*buffer), BUFFER_LEN, memcard)) != 0)
{
    if ((err = ferror(memcard)))
    {
        fclose(memcard);
        fprintf(stderr, "Error code: %d", err);
        perror("Error: ");
        return 1;
    }
    if (feof(memcard))
    {
        printf("reached before\n");
    }
    printf("fread bytes read: %d\n", count);
    ftell(memcard);
    if (feof(memcard))
    {
        printf("reached after\n");
    }
}

this triggers both the first if(feof) and the second if(feof)

As expected though, if I change the ftell to fseek(memcard, 0, SEEK_CUR), the EOF is reset and the reached after is never printed.

like image 231
Chase Avatar asked Jun 10 '20 11:06

Chase


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Video Answer


1 Answers

As some commentors pointed out, it ran into an EOF, and ftell actually got rid of that EOF. Why? To find the answer, we have to look inside glibc's source code. We can find the source for ftell::

long int
_IO_ftell (FILE *fp)
{
  off64_t pos;
  CHECK_FILE (fp, -1L);
  _IO_acquire_lock (fp);
  pos = _IO_seekoff_unlocked (fp, 0, _IO_seek_cur, 0);
  if (_IO_in_backup (fp) && pos != _IO_pos_BAD)
    {
      if (_IO_vtable_offset (fp) != 0 || fp->_mode <= 0)
    pos -= fp->_IO_save_end - fp->_IO_save_base;
    }
  _IO_release_lock (fp);
  if (pos == _IO_pos_BAD)
    {
      if (errno == 0)
    __set_errno (EIO);
      return -1L;
    }
  if ((off64_t) (long int) pos != pos)
    {
      __set_errno (EOVERFLOW);
      return -1L;
    }
  return pos;
}
libc_hidden_def (_IO_ftell)

weak_alias (_IO_ftell, ftell)

This is the important line:

pos = _IO_seekoff_unlocked (fp, 0, _IO_seek_cur, 0);

Let's find the source for _IO_seekoff_unlocked:

off64_t
_IO_seekoff_unlocked (FILE *fp, off64_t offset, int dir, int mode)
{
  if (dir != _IO_seek_cur && dir != _IO_seek_set && dir != _IO_seek_end)
    {
      __set_errno (EINVAL);
      return EOF;
    }

  /* If we have a backup buffer, get rid of it, since the __seekoff
     callback may not know to do the right thing about it.
     This may be over-kill, but it'll do for now. TODO */
  if (mode != 0 && ((_IO_fwide (fp, 0) < 0 && _IO_have_backup (fp))
            || (_IO_fwide (fp, 0) > 0 && _IO_have_wbackup (fp))))
    {
      if (dir == _IO_seek_cur && _IO_in_backup (fp))
    {
      if (_IO_vtable_offset (fp) != 0 || fp->_mode <= 0)
        offset -= fp->_IO_read_end - fp->_IO_read_ptr;
      else
        abort ();
    }
      if (_IO_fwide (fp, 0) < 0)
    _IO_free_backup_area (fp);
      else
    _IO_free_wbackup_area (fp);
    }

  return _IO_SEEKOFF (fp, offset, dir, mode);
}

Basically, it just does some checks then calls _IO_SEEKOFF, so let's find its source:

/* The 'seekoff' hook moves the stream position to a new position
   relative to the start of the file (if DIR==0), the current position
   (MODE==1), or the end of the file (MODE==2).
   It matches the streambuf::seekoff virtual function.
   It is also used for the ANSI fseek function. */
typedef off64_t (*_IO_seekoff_t) (FILE *FP, off64_t OFF, int DIR,
                      int MODE);
#define _IO_SEEKOFF(FP, OFF, DIR, MODE) JUMP3 (__seekoff, FP, OFF, DIR, MODE)

So basically, ftell ends up calling a function which is the equivalent of fseek(fp, 0, SEEK_CUR). And in the fseek standards we see: "A successful call to the fseek() function clears the end-of-file indicator for the stream." That's why ftell changes the behavior of the program.

like image 183
Aplet123 Avatar answered Sep 20 '22 16:09

Aplet123