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How does Arrays work in the ByteCode of Java [duplicate]

If I use a normal class like List, Vector or something else, I get a size() function which returns the length of the regarded class but if I use an array of a class or a default data type I get a public member length which returns the current length of the array.

int a[] = new int[3];
a.length; // used without ()

Vector<Integer> v = new Vector<Integer>();
v.length(); // used with ()

Why is that? I mean an array is not an own class isn't it? So if it is no class it can't have a member varaible. I can't get an idea how that is handled in the background (ByteCode). I know that an array in the memory is stored with a pointer to the first element of the array and with the index (i) the memory pointer is shifted to ArrayPointer + i*(size of DataType).

Now you can say the computer goes throught all elements of an array and counts all the elements but how can a computer know where an array ends and where the next starts? And from where comes the 'member varaible' from the array where the size is stored?

I mean we use arrays so often but I know so little what happens behind the Java code in the ByteCode. Can you explain to me how that is possible?

like image 410
Cilenco Avatar asked Dec 15 '22 03:12

Cilenco


1 Answers

Arrays are objects in Java, but they don't correspond to real classes. Effectively, the JVM implicitly creates array classes on the fly, but for performance reasons, they aren't actual classes.

Since they are objects, they can be stored in Object fields and passed around like normal. However, they are treated a bit differently at the bytecode level.

First off, arrays are created with the newarray, anewarray, or multinewarray instructions for single dimension primative, single dimension object, and multidimensional arrays respectively. By contrast, regular objects are created with the new instruction.

Getting and setting elements is done with the *aload and *astore instructions.

Also, x.length is not a real field. Instead it gets compiled to the arraylength instruction. This can be seen by compiling the following code.

public void test(int size){
    int[] x = new int[size];
    String[] y = new String[size];
    System.out.println(x.length);
    System.out.println(y.length);
}

results in the following bytecode

.method public test : (I)V
    .limit stack 2
    .limit locals 4
    iload_1
    newarray int
    astore_2
    iload_1
    anewarray java/lang/String
    astore_3
    getstatic java/lang/System out Ljava/io/PrintStream;
    aload_2
    arraylength
    invokevirtual java/io/PrintStream println (I)V
    getstatic java/lang/System out Ljava/io/PrintStream;
    aload_3
    arraylength
    invokevirtual java/io/PrintStream println (I)V
    return
.end method

Attempting to access the length field by manually creating bytecode will result in an exception, because the field doesn't actually exist.

.method static public main : ([Ljava/lang/String;)V
    .limit stack 1
    .limit locals 1
    aload_0
    getfield [Ljava/lang/String; length I
    return
.end method

results in

Exception in thread "main" java.lang.VerifyError: Expecting reference to class i
n class ArrayTest at constant pool index 30 in method ArrayTest.main([Ljava/lang
/String;)V
        at java.lang.Class.getDeclaredMethods0(Native Method)
        at java.lang.Class.privateGetDeclaredMethods(Unknown Source)
        at java.lang.Class.getMethod0(Unknown Source)
        at java.lang.Class.getMethod(Unknown Source)
        at sun.launcher.LauncherHelper.getMainMethod(Unknown Source)
        at sun.launcher.LauncherHelper.checkAndLoadMain(Unknown Source)
like image 61
Antimony Avatar answered Dec 17 '22 17:12

Antimony