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I'm compiling some code which uses libcurl on a Debian Linux system. My dev machine is running Debian 5 but I want the binary to be usable on older Debian 4 systems too.
I find that if I specify -lcurl it will link to libcurl.so.4 but Debian 4 systems only have libcurl.so.3
Is there some way I can tell GCC to link to either libcurl.so.3 (which exists in both Debian 4 and 5) or just libcurl.so so it will use whatever version is available ?
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6. Which option of GCC compiler provides the linking with shared libraries? Explanation: None.
Shared libraries (also called dynamic libraries) are linked into the program in two stages. First, during compile time, the linker verifies that all the symbols (again, functions, variables and the like) required by the program, are either linked into the program, or in one of its shared libraries.
As already mentioned here, the thing you probably want is the linker option -rpath . Like that, you can set a default search path for the binary. Looks like you even already use -rpath in your makefile, but you specify the wrong path: LIBS = -L$(LIB) -lfuse -lsqlite3 -lkw_taglib -ltag_c -ltag -Wl,-rpath=.
If you want to open a shared-library file, you would open it like any other binary file -- with a hex-editor (also called a binary-editor). There are several hex-editors in the standard repositories such as GHex (https://packages.ubuntu.com/xenial/ghex) or Bless (https://packages.ubuntu.com/xenial/bless).
Instead of using "-lcurl" use "-l:libcurl.so.3" And ofcourse also use "-L _installed_path_"
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You can pass the actual .so file instead of -l on the linker command line, and it ought to do what you want.
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