How do you escape try/catch hell in Javascript?

Question

Ok, I like(d) try/catch with await/async.

But what do I do with this.

I wanted to do this..

let a = await doAbc();
let b = await do123(a);

what it becomes instead is

let a, b;

try {
   a = await doAbc();
} catch(e) {
   a = await doZxc();
}

try { 
   b = await do123(a);
} catch (e) {
   console.log(e);
   return;
}

if (b.data == undefined) {
    return -1;
} else {
    return b;
}

At this point I'm regretting everything.

Answer 1

Remember that you can await any promise. So you could do:

let a = await doAbc().catch(doZxc); // or .catch(() => doZxc())
let b = await do123(a);

Or even

 let b = await doAbc().catch(doZxc).then(do123);

Together with the rest of your code:

try { 
  let b = await doAbc().catch(doZxc).then(do123);
  return b.data == undefined ? -1 : b;
} catch (e) {
   console.log(e);
   return;
}