How do you create a slice of functions with different signatures? I tried the code below but its feels hack-ish. Do we just bite the bullet and use a slice interface{}?
package main
import (
"fmt"
)
type OneParams func(string) string
type TwoParams func(string, string) string
type ThreeParams func(string, string, string) string
func (o OneParams) Union() string {
return "Single string"
}
func (t TwoParams) Union() string {
return "Double string"
}
func (t ThreeParams) Union() string {
return "Triple string"
}
type Functions interface {
Union() string
}
func Single(str string) string {
return str
}
func Double(str1 string, str2 string) string {
return str1 + " " + str2
}
func Triple(str1 string, str2 string, str3 string) string {
return str1 + " " + str2 + " " + str3
}
func main() {
fmt.Println("Slice Of Functions Program!\n\n")
fSlice := []Functions{
OneParams(Single),
TwoParams(Double),
ThreeParams(Triple),
}
for _, value := range fSlice {
switch t := value.(type) {
case OneParams:
fmt.Printf("One: %s\n", t("one"))
case TwoParams:
fmt.Printf("Two: %s\n", t("one", "two"))
case ThreeParams:
fmt.Printf("Three: %s\n", t("one", "two", "three"))
default:
fmt.Println("Huh! What's that?")
}
}
fmt.Println("\n\n")
}
Is this just a case of trying to do too much with Go?
A slice can also be formed by “slicing” an existing slice or array. Slicing is done by specifying a half-open range with two indices separated by a colon. For example, the expression b[1:4] creates a slice including elements 1 through 3 of b (the indices of the resulting slice will be 0 through 2).
A slice can be declare using new keyword followed by capacity in square brackets then type of elements the slice will hold.
After the parameters we put the return type. Collectively the parameters and the return type are known as the function's signature.
In Golang, we declare a function using the func keyword. A function has a name, a list of comma-separated input parameters along with their types, the result type(s), and a body. The input parameters and return type(s) are optional for a function. A function can be declared without any input and output.
Please check it, I don't know if it what you want. Because I don't know what are you exactly want.
package main
import (
"fmt"
"reflect"
)
func A() {
fmt.Println("A")
}
func B(A int) {
fmt.Println("B", A)
}
func C(A string, B float32) {
fmt.Println("C", A, B)
}
func main() {
f := []interface{}{A, B, C}
f[0].(func())()
f[1].(func(int))(15)
f[2].(func(string, float32))("TEST", 90)
fmt.Println("\n******* another thing ******")
for a, v := range f {
v := reflect.TypeOf(v)
fmt.Println("#######", a)
fmt.Println("num param :", v.NumIn())
for i := 0; i < v.NumIn(); i++ {
fmt.Println("param :", i, "type is ", v.In(i))
}
}
}
Check on Go Playground
Here I have another example calling using reflect
package main
import (
"fmt"
"reflect"
)
func A() {
fmt.Println("A")
}
func B(A int) {
fmt.Println("B", A)
}
func C(A string, B float32) {
fmt.Println("C", A, B)
}
func main() {
f := []interface{}{A, B, C}
f[0].(func())()
f[1].(func(int))(15)
f[2].(func(string, float32))("TEST", 90)
fmt.Println("\n******* calling with reflect ******")
for a, v := range f {
v := reflect.TypeOf(v)
//calling the function from reflect
val := reflect.ValueOf(f[a])
params := make([]reflect.Value, v.NumIn())
if v.NumIn() == 1 {
params[0] = reflect.ValueOf(1564)
} else if v.NumIn() == 2 {
params[0] = reflect.ValueOf("Test FROM reflect")
params[1] = reflect.ValueOf(float32(123456))
}
val.Call(params)
}
}
Check on Go Playground
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