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Ok this has been become sooo confusing to me. I just don't know what is wrong with this assignment:
void *pa; void *pb;
char *ptemp; char *ptemp2;
ptemp = (char *)pa;
ptemp2 = (char *)pb;
Can anyone tell me why I'm getting this error:
error: invalid conversion from ‘void*’ to ‘char*’
229
void* to char**You can't. You need reinterpret_cast. You have a 'pointer to anything' and have decided to treat it as a 'pointer to a char*'. That is 'reinterpreting' the type of the memory without applying any conversions.
Simply doing array = ptr; or char * array = ptr; would perfectly do. C "implicitly converts" to/from void -pointers.
A void pointer is a pointer that has no associated data type with it. A void pointer can hold address of any type and can be typecasted to any type.
After declaration, we store the address of variable 'data' in a void pointer variable, i.e., ptr. Now, we want to assign the void pointer to integer pointer, in order to do this, we need to apply the cast operator, i.e., (int *) to the void pointer variable.
I just tried your code in a module called temp.c. I added a function called f1.
void *pa; void *pb;
char *ptemp; char *ptemp2;
f1()
{
ptemp = (char *)pa;
ptemp2 = (char *)pb;
}
On Linux I entered gcc -c temp.c, and this compiled with no errors or warnings.
On which OS are you trying this?
21
Actually, there must be something wrong with your compiler(or you haven't told the full story). It is perfectly legal to cast a void* to char*. Furthermore, the conversion is implicit in C (unlike C++), that is, the following should compile as well
char* pChar;
void* pVoid;
pChar = (char*)pVoid; //OK in both C and C++
pChar = pVoid; //OK in C, convertion is implicit
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