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How do you convert a .CSR / p10 / PKCS#10 file to .DER format in java?

How do you convert a .CSR (a.k.a. p10 or PKCS#10) file to .DER format in java?

Here is a sample one:

-----BEGIN CERTIFICATE REQUEST-----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-----END CERTIFICATE REQUEST-----

Printing the CSR/P10 file

I know that I can use the Microsoft certutil command in windows to display it also.

Example:

cerutil -dump <filename.p10>

PKCS10 Certificate Request:
Version: 1
Subject:
    [email protected]
    O=case
    OU=test
    CN=bogus

Public Key Algorithm:
    Algorithm ObjectId: 1.2.840.113549.1.1.1 RSA (RSA_SIGN)
    Algorithm Parameters:
    05 00
Public Key Length: 2048 bits
Public Key: UnusedBits = 0
    0000  30 82 01 0a 02 82 01 01  00 9a f7 b9 3d f4 d7 c2
    0010  c4 de 0c aa c0 09 4f 41  b6 bf 6e fc 34 7f 96 1e
    0020  8e e7 4c 2d 06 b4 44 e0  1d 52 5f d8 cf 74 e5 54
    0030  32 81 f9 c4 0a f5 d4 d3  cd ae 75 16 25 86 2b 38
    0040  b4 c5 4f 58 64 e5 c3 7d  17 09 a0 53 c1 47 42 64
    0050  c3 4f 5e 87 97 c9 db 8a  04 b1 04 12 80 f7 97 d7
    0060  5a 58 35 a3 85 f2 fc 26  33 c6 a0 53 de 48 8c 58
    0070  b0 6c 8b 97 75 a3 98 da  9e df f4 fd 59 d8 6d 1f
    0080  61 9d aa df 8b 3e ad b9  a2 5d 52 86 fd 8b d3 6c
    0090  09 9b ec 1b 9a bc 9f 81  8b 07 5d 76 b2 6c 3f 85
    00a0  94 c8 49 ab f8 0c d0 d9  64 f1 4d 3a c4 37 1f 5b
    00b0  fb 6c 25 d2 ab a4 60 12  cb e6 95 93 8b 51 2a a1
    00c0  52 0c 22 4c 6a 5a 42 a3  87 80 2d 7b d2 f9 e2 8e
    00d0  25 52 7e 96 b2 b6 46 73  03 4e 73 d9 ab 78 76 73
    00e0  b7 f3 ad 4a bd b3 cd 10  83 74 d9 ee 7a 4f a3 c3
    00f0  6d 61 e6 b4 d5 7d e6 fe  dc 00 ca 58 38 c5 36 f8
    0100  62 a7 dc 60 67 a7 9c c4  a3 02 03 01 00 01
Request Attributes: 1
  1 attributes:

  Attribute[0]: 1.2.840.113549.1.9.7 (Challenge Password)
    Value[0][0]:
    Unknown Attribute type
    password
Signature Algorithm:
    Algorithm ObjectId: 1.2.840.113549.1.1.4 md5RSA
    Algorithm Parameters:
    05 00
Signature: UnusedBits=0
    0000  4a c4 54 33 4f 16 cd 24  9a 82 b9 a2 d1 01 71 4f
    0010  35 8d 0e 8e 81 d7 23 f3  df a6 01 fe 82 55 2a a1
    0020  c9 8a a6 e4 78 50 9d 02  5d a1 6f 8c a8 90 12 23
    0030  57 ec de 5a 87 22 b8 f0  d4 f9 c6 93 dc 00 36 0b
    0040  4f 80 4e 03 8d f3 09 55  67 e0 72 5d d9 da 02 ac
    0050  7e 00 c4 eb 04 3d 98 2d  e7 df 07 3a f7 85 8e f9
    0060  24 49 cf 40 d4 3f 24 43  d5 46 8c 7c bd fc fb 36
    0070  be b3 73 ca 9a 8a a1 cc  1d 5c ae a8 01 ac ab f3
    0080  26 4b 72 aa 7d ab 72 e3  7a 0a b4 bd d1 81 4e 69
    0090  4f 10 b1 b2 1c df eb c7  b1 b1 5c 43 65 b4 c1 62
    00a0  a1 50 f4 3e 1e e1 b3 c3  2b a7 22 55 fc 81 51 e7
    00b0  80 d2 fa a8 6d 41 cf 80  5f 46 06 7c 4e 48 13 09
    00c0  95 7d 09 b4 28 82 42 8f  18 ae 62 86 a8 79 6c 7b
    00d0  9c 12 db 79 d5 78 b2 dc  f9 17 71 8f ef 66 d7 69
    00e0  cc f7 c5 f0 ed 77 4f f7  8f 64 7f 27 35 cc e6 23
    00f0  8c 09 bf bf 70 6c 4c 70  37 47 fa 46 a6 e1 57 75
Signature matches Public Key
Key Id Hash(rfc-sha1): 3b 03 e4 49 e8 b4 74 99 43 84 9e a4 b6 27 c4 1f c0 c5 e7 6b
Key Id Hash(sha1): 17 68 43 78 9a 76 53 4c 24 3a 9a 8d 13 a0 47 c6 92 93 4c 84
CertUtil: -dump command completed successfully.

I also know that I can print the ASN.1 format as follows:
openssl asn1parse -in <filename>

    0:d=0  hl=4 l= 687 cons: SEQUENCE
    4:d=1  hl=4 l= 407 cons: SEQUENCE
    8:d=2  hl=2 l=   1 prim: INTEGER           :00
   11:d=2  hl=2 l=  81 cons: SEQUENCE
   13:d=3  hl=2 l=  14 cons: SET
   15:d=4  hl=2 l=  12 cons: SEQUENCE
   17:d=5  hl=2 l=   3 prim: OBJECT            :commonName
   22:d=5  hl=2 l=   5 prim: PRINTABLESTRING   :bogus
   29:d=3  hl=2 l=  13 cons: SET
   31:d=4  hl=2 l=  11 cons: SEQUENCE
   33:d=5  hl=2 l=   3 prim: OBJECT            :organizationalUnitName
   38:d=5  hl=2 l=   4 prim: PRINTABLESTRING   :test
   44:d=3  hl=2 l=  13 cons: SET
   46:d=4  hl=2 l=  11 cons: SEQUENCE
   48:d=5  hl=2 l=   3 prim: OBJECT            :organizationName
   53:d=5  hl=2 l=   4 prim: PRINTABLESTRING   :case
   59:d=3  hl=2 l=  33 cons: SET
   61:d=4  hl=2 l=  31 cons: SEQUENCE
   63:d=5  hl=2 l=   9 prim: OBJECT            :emailAddress
   74:d=5  hl=2 l=  18 prim: IA5STRING         :[email protected]
   94:d=2  hl=4 l= 290 cons: SEQUENCE
   98:d=3  hl=2 l=  13 cons: SEQUENCE
  100:d=4  hl=2 l=   9 prim: OBJECT            :rsaEncryption
  111:d=4  hl=2 l=   0 prim: NULL
  113:d=3  hl=4 l= 271 prim: BIT STRING
  388:d=2  hl=2 l=  25 cons: cont [ 0 ]
  390:d=3  hl=2 l=  23 cons: SEQUENCE
  392:d=4  hl=2 l=   9 prim: OBJECT            :challengePassword
  403:d=4  hl=2 l=  10 cons: SET
  405:d=5  hl=2 l=   8 prim: PRINTABLESTRING   :password
  415:d=1  hl=2 l=  13 cons: SEQUENCE
  417:d=2  hl=2 l=   9 prim: OBJECT            :md5WithRSAEncryption
  428:d=2  hl=2 l=   0 prim: NULL
  430:d=1  hl=4 l= 257 prim: BIT STRING
like image 824
atom88 Avatar asked Jan 16 '14 15:01

atom88


2 Answers

I found out that you can use the built in java converter for this:

byte[] certificateData = "....<YOUR PEM ENCODED DATA STRING HERE>...";

String certificateDataString = removeCSRHeadersAndFooters(new String(certificateData)); // remove headers and footers

byte[] derByteArray = javax.xml.bind.DatatypeConverter.parseBase64Binary(certificateDataString); // PEM -> DER

A convenience method for stripping out headers and footers

/**
 * Takes in a CSR/p10 as a string and removes the headers and footers of the request string.
 * 
 * @param inString a CSR string
 * @return a CSR String stripped of the text headers and footers
 */
public static String removeCSRHeadersAndFooters(String inString)
{
    logger.debug("pemString: [" + inString + "]");

    inString = inString.replace("-----BEGIN CERTIFICATE REQUEST-----" + "\n", "");
    inString = inString.replace("\n" + "-----END CERTIFICATE REQUEST-----" + "\n", "");

    logger.debug("[" + inString + "]");

    return inString;
}
like image 138
atom88 Avatar answered Oct 03 '22 15:10

atom88


One can make it simpler with only three lines and decode not only certificate requests, but certificates and signatures as well

public static byte[] pemToDer(String pem) {
    /* We split data with dashes as separator.
    As a result we should have either 5 parts or 1,
    if guarding strings were not present. */
    String[] parts = pem.split("-----");
    /* The middle element is base64 encoded data */
    String base64 = parts[parts.length / 2];
    return DatatypeConverter.parseBase64Binary(base64);
}
like image 39
divanov Avatar answered Oct 03 '22 14:10

divanov