How do you calculate how much faster time X is from time Y in terms of %? [closed]

Question

We're having a bit of a dispute at my office as to how this question should be interpreted.

**Time 1 = 0.6053 seconds Time 2 = 1.3477 seconds

What percentage faster is time1 to time 2?**

I am of the believe that if you have a time of X seconds. X/2 (half as long) is 100% faster.

My solution to this problem is calculated as

(T2/T1)-1

1.3477/.6053 - 1 = 1.2265

Other people are saying that you should just look at these as numbers and calculate it like

1- (T1/T2)

1- .6053/1.3477 = .5508

(the answers above are rounded).

Answer 1

It makes it easier to use whole numbers..

Lets say X = 100 and Y = 50

You're saying "What percentage faster is time 1 to time 2?" This means, with respect from time 2, how much faster is time 1... Again, using time 2 as the reference point, how does time 1 compare.

So for this, you would use: T1 / T2 = (100 / 50) = twice as fast = 200%

In your case above, X < Y so it would be a percentage less than 100%. Roughly 44.9% faster.