How do truncate string of certain length but include complete words after truncation

Question

I want to truncate substring from string upto 60 characters , but also want to get complete words within substring. Here is what I am trying.

String originalText =" Bangladesh's first day of Test cricket on Indian soil has not been a good one. They end the day having conceded 71 runs in the last 10 overs, which meant they are already staring at a total of 356. M Vijay was solid and languid as he made his ninth Test century and third of the season. ";
String afterOptimized=originalText.substring(0, 60);
System.out.println("This is text . "+afterOptimized);

Here is output

This is text .  Bangladesh's first day of Test cricket on Indian soil has n

However mine requirement is to not cut the words in between.How do I know there is complete words or not after 60 characters.

Answer 1

You can use regular expression for this, taking up to 60 characters and ending at word boundary:

Pattern pattern = Pattern.compile("(.{1,60})(\\b|$)(.*)");
Matcher m = pattern.match(originalText);
If (m.matches())
    afterOptimized = m.group(1);

Or, in a loop:

Pattern pattern = Pattern.compile("\\s*(.{1,60})(\\b|$)");
Matcher m = pattern.matcher(originalText);
int last = 0;
while (m.find()) {
    System.out.println(m.group(1));
    last = m.end();
}
if (last != originalText.length())
    System.out.println(originalText.substring(last));

You may want to replace \b with \s if you want to wrap only at white space instead of word boundary (which may wrap before comma, dots etc).